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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the number of structure isomers of fully saturated cycloalkane of molecular formulae `C_(6)H_(12)` which give the monochloro structural products. |
| Answer» Correct Answer - 3 | |
| 2. |
Only two isomeric monochloro derivatives are possible for :-A. `n`-PentaneB. `2,4`-Dimethyl pentaneC. TolueneD. `2,3`-Dimethyl butane |
| Answer» Correct Answer - D | |
| 3. |
(i) In sulphur estimation , 0.157 g of organic compound gave 0.4813 g of `BaSO_(4)`. What is the percentage of sulphur in organic compound ? (ii) 0.092 g of organic compound heating is carius tube and susequent ignition gave 0.111 g of `Mg_(2)P_(2)O_(7)` . calculate the percentage of phosphorus in organic compound. |
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Answer» (i) Mass of `BaSO_(4) `=0.4813 g , mass of organic compound =0.157 g % S `=(32xxW_(BaSO_(4))xx100)/(233xxW_("Substance"))=(32xx0.4813xx100)/(233xx0.157) =42.10` (ii) Mass of organic compound =0.092 g , mass of `Mg_(2)P_(2)O_(7) `=0.111 g % of P =`(62xxW_(Mg_(2)P_(2)O_(7))xx100)/(22xxW_("Substance"))=(62xx0.111xx100)/(222x0.092)=33.69` |
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| 4. |
On mixing a certain alkane with chlorine and irradiating it with ultraviolet light, it forms only one monochloroalkane this alkane could be :A. propaneB. pentaneC. isopentaneD. neopentane |
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Answer» Correct Answer - D The numberof monohalogenation products obtained from any alkane depends upon the number of different types of hydrogen it contains. Compound containng only one type of hydrogen gives only one monohalogenation product. `{:(underset("propane")(CH_(3)CH_(2)CH_(3)),-,underset(("two monohalogenation structural product"))("two types of hydrogen"),),(underset("pentane")(CH_(3)CH_(2)CH_(2)CH_(3)),-,underset(("two monohalogenation structural product"))("three types of hydrogen"),),(underset("isopentane")(CH_(3)-overset(CH_(3))overset(|)(CH)-CH_(2)-CH_(3)),-,"four types of hydrogen" " " ("four monohalogenation structural product"),),(H_(3)C-underset("neopentane")(underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C )-CH_(3)),-,"one types of hydrogen" " " ("one monohalogenation structural product"),):}` Thus the given alkane should be beopentane. |
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| 5. |
Observe the following compounds |
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Answer» Correct Answer - 8(5+3) Compound (I),(IV),(V),(VII) and (IX) gives positive haloform compound (III),(VII) and (IX) gives positive lucas reagent , x=5,y=3 so, (5+3)=8. |
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| 6. |
A gaseous hydrocarbon has 85% carbon and vapour density of 28. The possible formula of the hydrocarbon will beA. `C_(3)H_(6)`B. `C_(2)H_(4)`C. `C_(2)H_(2)`D. `C_(4)H_8` |
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Answer» Correct Answer - D Mol . Wt. 2 x Vapour density =2 x 28 =56 |
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| 7. |
The following two compounds `I` and `II` can be distinguished by using reagent (a) aq. `NaHCO_(3)` " " (b) Neutral `FeCl_(3)` (c ) Fehling solution " " (d) `Na` metalA. `a` or c`B. `b` or c`C. `c` or `d`D. `b` ro `d` |
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Answer» Correct Answer - B (a) Both does not give the test with aq. `NaHCO_(3)`. (v) `II` give `+ve` test with neutral `FeCl_(3)` due to presence of phenolic `-OH` group, but `(I)` does not. ( c) In `(I)` aromatic aldehyde does not give Fehling test but `(II)` gives. (d) In `(I)` and `(II)` acidic hydrogen atom is present so both give `+ve` test with `Na` metal. |
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| 8. |
The following two compounds `I` and `II` can be distinguished by using reagent " " (a) aq. `NaHCO_(3)` " " (b) Neutral `FeCl_(3)` (c ) Blue litmus solution " " `Na` metal " " (e) `HCl//ZnCl_(2)` anhydrousA. `a` or c`B. `b` or `e`C. `d` or `e`D. `c` or `d` |
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Answer» Correct Answer - B (a) Both give the test with `aq`. `NaHCO_(3)` because both have `-COOH` group and acidic hydrogen. (b) `II` give `+ ve` test with neutral `FeCl_(3)` due to presence of phenolic `-OH` group, but `(I)` does not. ( c) In`(I)` and `(II)` acidic hydrogen atom is present so both give `+ve` test with blue litmus solution. (d) In `(I)` and `(II)` acidic hydrogen atom is present so both give +`ve` test with `Na` metal. (e) `(I)` give `+ve` test with `HCl//ZnCl_(2)` due to presence of aliphatic alcoholic group, but `(II)` does not. |
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| 9. |
Correct statement `(s)` about is`//`areA. It gives coloured solution with neutral `FeCl_(3)` solution.B. It liberates `H_(2)` gas with `Na` metal.C. It gives `+ve` Iodoform test.D. It forms sweet smelling compound with alcohols. |
| Answer» Correct Answer - A::B::C | |
| 10. |
Correct statement `(s)` about is`//`areA. It gives coloured solution with neutral `FeCl_(3)` solution.B. It liberates `H_(2)` gas with `Na` metal.C. It gives `+ve` Iodoform test.D. It forms sweet smelling compound with alcohols. |
| Answer» Correct Answer - A::B::C | |
| 11. |
Which of the following compound will not react with `l_(2)//OH^(-)`.A. B. C. D. `CH_3-CHO` |
| Answer» Correct Answer - C | |
| 12. |
Which of the following perfome reaction with `I_(2)//OH^(-)` ?A. `CH_(3)COCH_(2)CH_(3)`B. `CH_(3)CONH_(2)`C. `C_(6)H_(5)COCH_(3)`D. `CH_(3)CHO` |
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Answer» Correct Answer - A::C::D `CH_(3)CO-R` group without electron withdrawing group at `beta` position of `-C=O` will give idoform test. |
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| 13. |
How many no. of active Hydrogen atoms are present in compound (mol. Mass `90`) `0.45 g` of which when treated with `Na` metal liberates `112m l` of the `H_(2)` gas at `STP`. |
| Answer» Correct Answer - No. of active `H = 2` | |
| 14. |
For the estimation of nitrogen, `1.4 g` of an organic compound was digested by Kjeldahl method and the evolved ammonia was absorbed in `60 mL` of `(M)/(10)` sulphuric acid. The unreacted acid required `20 mL` of `(M)/(10)` sodium hydroxide of complete neutralization. The percentage of nitrogen in the compound is:A. `6%`B. `10%`C. `3%`D. `5%` |
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Answer» Correct Answer - B Mass of organic compound `= 1.4 g` let it contain `x m` mole of `N` atom. organic compound `rarr NH_(3)` `2NH_(3)+ underset("initial taken.")underset(6 "mmole")(H_(2)SO_(4)) rarr (NH_(4))_(2)SO_(4).(1st)` `H_(2)SO_(4)underset("reacted")underset("2 mmole")(+2NaPH) rarr Na_(2)SO_(4)+2H_(2) (2nd)` Hence `m` moles of `H_(2)SO_(4)` reacted in `2nd` equation `=1` `rArr m` moles of `H_(2)SO_(4)` reatced from `1st` equation `= 6-1 = 5m` moles `rArr m` moles of `NH_(3)` in `1st` equation `= 2 xx 5 = 10 m` moles `rArr m` moles of `N` atom in the organic compound `= 10 m` moles `rArr %` of `N = (0.14)/(1.4) xx 100 = 10%` |
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| 15. |
In compound `A (C_(30)H_(60)O)` following tests are observed negatively, A can be A. an unsaturated etherB. an epoxideC. a cyclic ketoneD. a cycloalkanol |
| Answer» Correct Answer - B | |
| 16. |
How many isomeric alkyne on hydrogenation gives `3,3`-Dimethylhexane. |
| Answer» Correct Answer - `3` | |
| 17. |
Structural of Ascorbic acid is represented as follows How many of the following reagents can gives positive test with ascorbic acid. `{:(Cu_(2)Cl_(2)+NH_(4)OH,"2,4"-DNP,"Na Metal",HCL+ZnCl_(2),FeCl_(3)),(" (I)"," (II)"," (III)"," (IV)","(V)"),("NAOH+Phenophthalein",dil. KMNO_(4),Br_(2)//H_(2)O,AgNO_(3)+NH_(4)OH,I_(2)+NaOH),(" (VI)"," (VII)"," (VIII)"," (IX)","(X)"):}` Number of compound which gives positive Haloform test=(x) Number of compound which can gives positive Lucas reagent test=(y) Report your answer (x+y) |
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Answer» Correct Answer - 6 Na Metal `HCl+ZnCl_(2), FeCl_(3), NaOH` +Phenolpthalein, dill `KMnO_(4)`, `Br_(2)//H_(2)O` gives positive test with ascorbic acid. |
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| 18. |
Calculate the `DU` of following compounds : (i) `C_(6)H_(6)ClBrO` , (ii) `C_(5)H_(9)N` |
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Answer» Correct Answer - (i) `3` , (ii) `2` (i) `D u = (6+1 -8//2) = 3` " " (ii) `D U = 5+1 -((9-1)/(2)) = 2` |
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| 19. |
Alkynes `(A)` and `(B)` hav ethe molecular formula `C_(8)H_(14)` giving following reactions: (A) or (B) `overset(H_(2)//Pt)rarr "n-Octane"`. `(A) overset(O_(3)//H_(2)O)rarr CH_(3)CH_(2)CH_(2)CO_(2)H` (B) `overset(Ag(NH_(3))_(2)OH)rarr` silver containing white ppt. Write the structure of `(A)` and `(B)`. |
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Answer» Correct Answer - N//A Since `(A)` and `(B)` by reduction using `H_(2)//Pt` gives `n`-Octane, hence both have straight chain `A overset(O_(3)//H_(2)O)rarr CH_(3)CH_(2)CH_(2)CO_(2)H` ("and no other compound") Hence, there should be two mole of this acid. Thus `A` is `CH_(3)CH_(2)CH_(2)C-=C CH_(2)CH_(2)CH_(3)` `B` gives white ppt. containing `Ag` hence, `B` is terminal alkyne. Structure of `B` is `CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)CH_(2)C-=CH` |
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| 20. |
Which one gives idoform test in Ethanol and `n`-Propanol and why does the other one not so? |
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Answer» Correct Answer - N//A Ethanol gives iodoform test because on oxidation it gives `CH_(4)-overset(O)overset(||)(C )-H` i.e., it has `CH_(3)-overset(O)overset(||)(C )-` group whereas `n`. Propanol on oxidation gives `CH_(3)-CH_(2)-overset(O)overset(||)(C )-H` which does not have `CH-overset(O)overset(||)(C )` group therefore it will not respond to iodoform test. |
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| 21. |
Red precipitate `underset(NH_(4)OH)overset(Cu_(2)Cl_(2))larrP(C_(5)H_(8))overset("Ozonolysis")rarr2`-Methylpropanoic acid `+` compound `(Q)` structure of `P` can be-A. `CH_(3)-CH_(2)-CH_(2)-C-=CH`B. `CH_(3)-underset(CH_(3))underset(|)(CH)-C-=CH`C. `CH_(3)C=C-CH_(2)-CH_(3)`D. `CH_(3)-underset(CH_(3))underset(|)(CH)-CH=CH_(2)` |
| Answer» Correct Answer - B | |
| 22. |
Write the structure and give `IUPAC` name of the alkane which gives only Pentan-`2`-one on reductive ozonolysis, |
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Answer» Correct Answer - N//A `underset("4,5-Dimethyloct-4-ene")(CH_(3)-CH_(2)-CH_(2)-overset(CH_(3))overset(|)(C )=overset(CH_(3))overset(|)(C )-CH_(2)-CH_(2)-CH_(3))underset((ii) Zn_(1)H_(2)O)overset((i) O_(3))rarrunderset("pentan-2-one")(2CH_(5)-CH_(2)-CH_(2)-overset(O)overset(||)(C )-CH_(3))` |
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| 23. |
Which alkene on reductive ozonolysis will produce Acetaldehyde only ? |
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Answer» Correct Answer - N//A Alkene is But-`2`-ene. `underset("But-2-ene")(CH_(3)-CH=CH-CH_(3))underset((ii)Zn_(1)H_(2)O)overset((i)O_(3))rarr2CH_(3)-CH=O` |
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| 24. |
, `CH_(3)CH_(2)COOH` Identify `X`:A. `CH_(3)-CH_(2)-C-=C-CH_(2)-CH_(3)`B. `CH_(3)-C-=CH_(2)-CH_(2)-CH_(3)`C. D. |
| Answer» Correct Answer - A | |
| 25. |
Which of the following can gives hinsberg testA. `CH_(3)-CH_(2)-OH`B. `CH_(3)-CH_(2)-NO_(2)`C. `CH_(3)-CH_(2)-NH_(2)`D. `CH_(3)-underset(O)underset(||)(C)-NH_(2)` |
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Answer» Correct Answer - C Amines give positive hinsberg test. |
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| 26. |
An organic compound `X (C_(4)H_(8)O_(2))` gives positive teast with `NaOH` positive test with `NaOH` and Phenopthalein. Structure of `X` will be:A. `CH_(3)-CH_(2)-CH_(2)-underset(O)underset(||)NH_(2)`B. `CH_(3)-underset(O)underset(||)C-underset(O)underset(||)C-CH_(3)`C. `CH_(3)-underset(O)underset(||)C-O-C_(2)H_(5)`D. `CH_(3)-underset(O)underset(||)C-OCH_(3)` |
| Answer» Correct Answer - C | |
| 27. |
Which of the following compound will give smell of `NH_(4)` with conc. `NaOH`.A. `CH_(3)-CH_(2)-underset(O)underset(||)C-NH_(2)`B. `CH_(3)-underset(O)underset(||)C-CH_(2)-NH_(2)`C. D. `CH_(3)-CH_(2)-underset(O)underset(||)C-OH` |
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Answer» Correct Answer - A Amide gives smell of `NH_(3)` with conc. `NaOH`. |
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| 28. |
Which of the following will not give positive test with `CHCl_(3)//KOH`.A. `CH_(3)-CH_(2)-NH-CH_(3)`B. `CH_(3)-CH_(2)-CH_(2)-NH_(2)`C. D. `CH_(3)-overset(CH_(3))overset(|)(CH)-NH_(2)` |
| Answer» Correct Answer - A | |
| 29. |
Which of the following compounds gives red ppt with `Cu_(2)Cl_(2)//NH_(4)OH` ?A. `CH_(3)-C-=C-CH_(3)`B. `CH_(3)-CH_(2)-C-=CH`C. `CH_(3)-CH_(2)-CH=CH_(2)`D. `CH_(3)-C-=C-CH=CH_(2)` |
| Answer» Correct Answer - B | |
| 30. |
, Instant turbidity Identyfy `X` :A. `CH_(3)-overset(CH_(3))overset(|)(CH)-underset(OH)underset(|)(CH)-CH_(3)`B. `CH_(3)-overset(CH_(3))overset(|)underset(OH)underset(|)(C)-CH_(2)-CH_(3)`C. `CH_(3)-overset(CH_(3))overset(|)(CH)-CH_(2)-CH_(2)-OH`D. `CH_(3)-overset(OH)overset(|)(CH)-CH_(2)-CH_(2)-OH` |
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Answer» Correct Answer - B `3^(@)` alcohol gives instant turbidity with lucas reagent. |
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| 31. |
Which of the following hydrocarbons give same product on hydrocarbonation :A. `2`-Methyl hex-`1`-ene & `3`-Methyl hex -`3`-eneB. `3`-Ethyl hex-`1`en-`4`-yne & `2`-Methylhpet-`2`-en-`4`-yneC. `3`-Ethylcycloprop-`1`-ene & `1,2`-Dimethylcycloprop-`1`-eneD. `2`-Methylbut-`2`- ene & `3`-Methylbut-`1`-ene |
| Answer» Correct Answer - D | |
| 32. |
A reaserch scholar get a mixture of three product during an experimant with ammonia. In product `I` only one `H` of ammonia is replaced by ethyl group and in `II` two `H` atoms of ammonia are replaced by ethyl groups and in `III` alll the `H`-atoms are replaced by ethyl groups. Which test he should use to distinguish or separate the products :A. Carbyl amine testB. Iodoform testC. Fehling solution testD. Hinsberg test |
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Answer» Correct Answer - D `1^(@), 2^(@)` and `3^(@)` amine mixture can be separated by Hinsberg reagent. |
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| 33. |
Test to differentiate between ethanol `(CH_(3)CH_(2)OH)` and phenol (Ph-OH) is /areA. Litmus testB. Neutral `FeCl_(3)`C. Sodium metal testD. all of these |
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Answer» Correct Answer - B Ethanol can got give neutral `FeCl_(3)` test but phenol gives this test. |
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| 34. |
How many of the following compounds decolorise `Br_(2)` water solution ? |
| Answer» Correct Answer - 5 | |
| 35. |
How many products (structure isomers only) are formed by monochlorination of given compound ? A. `6`B. `7`C. `8`D. `9` |
| Answer» Correct Answer - B | |
| 36. |
How many structures possibles for a compound with the molecular formula `C_(6)H_(12)O` which can give positive iodoform and `2,4-DNP` test. |
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Answer» Correct Answer - 4 `CH_(3)-CH_(2)-CH_(2)-CH_(2)-underset(O)underset(||)(C )-CH_(3)` " " `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-underset(O)underset(||)(C )-CH_(3)` `CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-underset(O)underset(||)(C )-CH_(3)` " " `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C )-underset(O)underset(||)(C )-CH_(3)` |
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| 37. |
A compound `X (C_(5)H_(10)O)` reacts with `2,4`-DNP but does not give silver mirror test and Iodoform reaction. The possible structure for `X` is : |
| Answer» Correct Answer - `CH_(3)-CH_(2)-overset(O)overset(||)(C )-CH_(2)-CH_(3)` | |
| 38. |
Among the following the one that gives positive iodoform test upon reaction with `I_(2)` and `NaOH` is ?A. `CH_(3)CH_(2)Ch(OH)CH_(2)CH_(3)`B. `C_(6)H_(5)CH_(2)CH_(2)OH`C. `CH_(3)-underset(CH_(2)-OH)underset(|)(CH)-CH_(3)`D. `PhCHOHCH_(3)` |
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Answer» Correct Answer - D For positive iodoform test, alcohol molecules must have `CH_(3)-underset(OH)underset(|)(CH)-` group `Ph-underset(OH)underset(|)(CH)-CH_(3)overset(I_(2)+NAOH)rarrCHI_(3)+Ph-COO^(-)`. |
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| 39. |
The degree of unsaturation of following compound `C_(8)H_(12)O, C_(3)H_(5)N, C_(4)H_(8)O` are respectively :A. `4,3,2`B. `3,2,1`C. `2,1,3`D. `2,2,3` |
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Answer» Correct Answer - A::B::C Degree of unsaturation `= ("No. of carbon atom +1")-("No. of H-atom + No. of halogen atom-No. of nitrogen atom")//2`. |
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| 40. |
Number of moles of hydrogen will required for complete hydrogenation of one mole of following compounds : A. `6`B. `7`C. `5`D. `3` |
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Answer» Correct Answer - C Number of mole of hydrogen needed is `=` number of double bonds `=5` |
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| 41. |
Identify the hydrocarbon having molecular formula `C_(5)H_(6)` which gives white ppt with ammonical `AgNO_(3)` ?A. B. C. D. |
| Answer» Correct Answer - A | |
| 42. |
Which of the following compounds will not give positive iodoform test. Acetophenone, Benzophenone, `2`-Pentanone, `3`-Pentanone, Acetaldehyde, `CH_(3)COCH_(3), (CH_(3))_(2)CHOH, (CH_(3)CH_(2))_(2)CH-OH, CH_(3)COOH, CH_(3)CONH_(2), CH_(3)COOCH_(3), CH_(3)COCl` |
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Answer» Correct Answer - Benzophenone, `3`-Pentanone, `(CH_(3)CH_(2))_(2)C-OH, CH_(3)COOH, CH_(3)COOH, CH_(3)CONH_(2), CH_(3)-COOCH_(3), CH_(3)COCl` `(CH_(3)-underset(O)underset(||)(C )-)` group give positive iodoform test but acids and acid derivatives do not. |
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| 43. |
Which of the following compound will give four monochloro (structural) product on monochlorination.A. B. C. D. |
| Answer» Correct Answer - D | |
| 44. |
which of the following compound cannot give iodoform when react with `IO^(-)` (hypolodite)A. `CH_(3)-underset(O)underset(||)(C)-OH`B. `Ph-underset(O)underset(||)(C)-CH_(3)`C. D. |
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Answer» Correct Answer - A `(CH_(3)-underset(O)underset(||)(C)-),(CH_(3)-underset(OH)underset(|)(OH)-)` groups gives positive iodoform test. |
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| 45. |
Write the product of following reactions : (a) `CH_(3)-overset(H_(3)C)overset(|)(C )=overset(CH_(3))overset(|)(C )-CH_(3) underset(Zn//H_(2)O)overset(O_(3))rarr` , (b) `CH_(3)-C-=C-CH_(3) underset(Zn//H_(2)O)overset(O_(3))rarr` ( c) `CH_(3)-C-=C-CH_(3)overset(O_(3)//H_(2)O_(2))rarr` , (d) `CH_(3)-overset(CH_(3))overset(|)(C )=CH-CH_(3) overset(O_(3)//H_(2)O_(2))rarr` |
| Answer» Correct Answer - (a) `CH_(3)-overset(CH_(3))overset(|)(C )=O` , (b) `CH_(3)-underset(O)underset(||)(C )-underset(O)underset(||)(C )-CH_(3)`, (c ) `CH_(3)-COOH` , (d) `CH_(3)-overset(CH_(3))overset(|)(C )=O+CH_(3)-overset(O)overset(||)(C )-OH` | |
| 46. |
`X overset(O_(3)//Zn)rarr` , The `IUPAC` name of compound `Y` is :A. `2`-CyclohexylbutaneB. `1`-MethylpropylcyclohexaneC. ButylcyclohexaneD. `1`-Cyclohexylbutane |
| Answer» Correct Answer - B | |
| 47. |
In Carius method of estimation of halogens, `250 mg` of an organic compound gave `141 mg` of `AgBr`. The percentage of bromine in the compound is: (at mass `Ag=108 , Br =80`)A. `24`B. `36`C. `48`D. `60` |
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Answer» Correct Answer - A `% X = ("Atomic mass of Br")/("Molecular mass of AgBr") xx ("Wt. of AgBr")/("Wt. of organic Bromide")` Thus `% Br = (80)/(188) xx (141)/(250) xx 100 = 24`. |
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| 48. |
Identify a reagent from the folloiwng list which can easily distinguish between `1`-butyne and `2`-butyne.A. bromine, `C Cl_(4)`B. `H_(2)//Ni`C. dilute `KMnO_(4)`D. ammonical `Cu_(2)Cl_(2)` solution |
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Answer» Correct Answer - D `CH_(3)-CH_(2)-C-=CHunderset(NH_(4)OH)overset(Cu_(2)Cl_(2))rarrunderset("Blood red colour")(CH_(3)-CH_(2)-C-=overset(Θ)(C )Coverset(o+)(u))+NH_(4)Cl+H_(2)O` |
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| 49. |
Molisch reagent is used to identify following compound ?A. GlucoseB. FructoseC. `D`-oxyriboseD. All of these |
| Answer» Correct Answer - D | |
| 50. |
Which of the following compounds gives azo dye test ?A. B. C. D. |
| Answer» Correct Answer - B | |