169 + Interview Questions in THE-OXYGEN-FAMILY IN GENERAL AWARENESS Page 3 InterviewSolution

101.	The element which shows maximum catenation in Group 16 isA. OB. SC. SeD. Po.
Answer» Correct Answer - B In Group 16, sulphur, S shows maximum catenation

Discussion

102.	In case of the hydrides `H_2O, H_2S, H_2Se` and `H_2Te` the acid strength of aqueous solution of equimolar concentration.A. increases with increasing thermal stability of the hydrideB. increases with decreasing thermal stability of the hydrideC. is no related to the thermal stability of the hydrideD. increases with increasing volatility of the hydride
Answer» Correct Answer - B Increasing order of acidic strength (and decreasing order of thermal stability) is `H_2O lt H_2S lt H_2Se lt H_2Te`

Discussion

103.	`SO_3` can be obtained byA. `S+H_2SO_4`B. `H_2SO_4 + PCl_5`C. `CaSO_4 +C `D. Heating ferric sulphate
Answer» Correct Answer - D Only ferric sulphate on heating gives `SO_3` `Fe_2(SO_4)_3overset(Delta)to Fe_2O_3+3SO_3` Other reactions do not give `SO_3` `S+2H_2SO_4 overset(Delta)to3SO_2+2H_2O` `H_2SO_4+2PCl_5 tounderset("Sulphuryl chloride")(SO_2Cl_2)+2POCl_3+2HCl` `CaSO_4 + 4C overset(Delta)to CaS+4CO`

Discussion

104.	Which has maximum number of oxo groups ?A. `H_2SO_4`B. `H_2SO_3`C. `H_3PO_3`D. `H_3PO_4`
Answer» Correct Answer - A Oxo group means M = O group `HO-undersetundersetunderset((H_2SO_4))(O)(\|\|)oversetoverset(O)(\|\|)S-OH " " HO-underset((H_2SO_3))oversetoverset(O)(\|\|)S-OH` `HO-undersetundersetunderset((H_3PO_4))(OH)(\|)oversetoverset(O)(\|\|)P-OH " " HO-underset((H_2PO_3))undersetunderset(H)(\|)oversetoverset(O)(\|\|)P-OH` `H_2SO_4` has maximum number of oxo groups (two).

Discussion

105.	Which of the following statements are incorrect about the oxidation state and acidic nature of oxo-acids?A. `SO_3` is a stronger oxidising agent and more acidic than `SO_2`B. Selenium form only two oxo-acids i.e. selenous acid `(H_2SeO_3)` and selenic acid `(H_2SeO_4)`C. The acidic strength and oxidising power of oxo-acids is greater in +6 oxidation state than in +4 oxidation stateD. None of these
Answer» Correct Answer - D All are correct statements

Discussion

106.	Which of the following is incorrect ?A. `O_2` is weaker oxidant than `O_3`B. `O_2` has larger bond length than `O_3`C. Both `O_2` and `O_3` are paramagneticD. `O_2` is linear and `O_3` is angular in shape.
Answer» Correct Answer - C `O_2` is a weaker oxidising agent than `O_3`(A) `O_3` has larger bond length than `O_2`(B) `O_2` is linear and `O_3` is angular in shape (D). Statement C is not correct. Correct statement : `O_2` is paramagnetic while `O_3` is diamagnetic .

Discussion

107.	Which of the following statements regarding sulphur is incorrect?A. The vapour at `200^(@)C` consists mostly of `S_8` ringsB. At `600^(@)C` the gas mainly consists of `S_2` moleculesC. The oxidation state of sulphur is never less than +4 in its compoundsD. `S_2` molecule is paramagnetic.
Answer» Correct Answer - B ONCl and `ONO^(-)` are isoelectronic

Discussion

108.	Identify the incorrect statement from the following:A. oxides of nitrogen in the atmosphere can cause the depletion of ozone layerB. ozone absorbs the intense ultraviolet radiation of the sunC. Depletion of ozone layer is because of its chemical reactions of chloro fluoro alkanes.D. Ozone absorbs infra red radiation.
Answer» Correct Answer - D `H_2O (H-O-H)` contains no `pi` -bond `Olarroverset(.)N=O,O=C=O and O = overset(ddot)N=O` contain one or more `pi` bonds

Discussion

109.	Which of the following statements regarding sulphur is incorrect?A. `S_2` molecule is paramagneticB. The vapour at `200^(@)C` consists mostly of `S_8` ringC. At `600^(@)C` the gas mainly consists of `S_2` moleculeD. The oxidation state of sulphur is never less than +4 in its compounds.
Answer» Correct Answer - D (C ) Sulphur may have -2 and +2 oxidation states also .

Discussion

110.	The element which has a simple cubic lattice in solid state isA. SeB. TeC. PoD. None of these
Answer» Correct Answer - C The only element which exists in simple cubic lattice in solid state is polonium (Po).

Discussion

111.	A group 16 element exists in monoatomic state in the metallic lattice. It also exists in two crystalline forms. The metal isA. PoB. SC. SeD. Te
Answer» Correct Answer - A Po is monoatomic. It exists in two crystalline forms. It is a metal

Discussion

112.	Which of the following has the largest size?A. `S^(2-)`B. `Se^(2-)`C. `O^(2-)`D. `Te^(2-)`
Answer» Correct Answer - D (A)`Fe_2(SO_4)_3oversetDeltatoFe_2O_3+3SO_3` (B)`S+H_2SO_4oversetDeltato3SO_2+2H_2O` (C )`CaSO_4+Coverset(Delta)toCaO + SO_2 +CO` (D)`H_2SO_4+PCl_5overset(Delta)tounderset("Chlorosulphonic acid")(HSO_3Cl+POCl_3)+HCl`

Discussion

113.	Which of the following process is used for extraction of sulphur from sulphur beds?A. Acheson processB. Carter processC. Frasch processD. Le-Blanc process.
Answer» Correct Answer - D Sulphur is extracted from sulphur beds by Frasch process while it is obtained as a by-product from alkali waste of Leblanc process. Acheson process is used for making graphite.

Discussion

114.	Which one of the following charrs when warmed with concentrated `H_2SO_4` ?A. CarbohydratesB. ProteinsC. FatsD. Hydrocarbon.
Answer» Correct Answer - A Carbohydrates get charred due to dehydration

Discussion

115.	When sulphur is boiled with `Na_(2)SO_(3)` solution, the compound formed isA. Sodium sulphideB. Sodium sulphateC. Sodium persulphateD. Sodium thiosulphate.
Answer» Correct Answer - B `Na_2SO_3+Sunderset("Boil")overset("Alkaline solution")tounderset("Sod. thiosulphate")(Na_2S_2O_3)`

Discussion

116.	Which of the following is not a reducing agent ?A. `SO_2`B. `H_2O`C. `CO_2`D. `NO_2`
Answer» Correct Answer - C `CO_2` is not a reducing agent as carbon cannot increase its oxidation state beyond 4 (O.S. of C in `CO_2`=4)

Discussion

117.	Assertion: Reaction of `SO_(2)` and `H_(2)S` in the presence of `Fe_(2)O_(3)` catalyst gives elemental sulphur. Reason: `SO_(2)` is a reducing agent.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true
Answer» Correct Answer - B Reason. `SO_2 +2H_2S .^(Fe_2O_3) 3S + 2H_2O` In this reaction `SO_2` is an oxidising agent and `H_2S` is a reducing agent. However, `SO_2` can also act as a reductant agent.

Discussion

118.	Which oxide of sulphur is capable of acting as oxidising as well as reducing agent?A. `SO_3`B. `SO_2`C. `S_2O_3`D. SO.
Answer» Correct Answer - B `SO_2` can act both as oxidising as well as reducing agent.

Discussion

119.	Which of the following does not exist freely in nature but is a strong reducing agent ?A. `H_2SO_4`B. `H_2SO_3`C. `H_2SO_5`D. `H_2S_2O_8`
Answer» Correct Answer - B

Discussion

120.	Bond angle is minimum forA. `H_2O`B. `H_2S`C. `H_2Se`D. `H_2Te`
Answer» Correct Answer - D Bond angle of group 16 hydrides decreases down the group. Therefore, `H_2Te` has minimum bond angle

Discussion

121.	`SO_3` when absorbed in 98% `H_2SO_4` it formsA. More concentrated `H_2SO_4 `B. `H_2SO_3`C. `H_2S_2O_8`D. `H_2S_2O_7`
Answer» Correct Answer - D `H_2SO_4 +SO_3to underset("Oleum")(H_2S_2O_7)`

Discussion

122.	Which form of sulphur exists in the form of zig-zag chains ?A. RhombicB. PlasticC. MonoclinicD. None
Answer» Correct Answer - B Plastic sulphur exists as zig-zag chain.

Discussion

123.	Assertion (A) : Ordinary sulphur exists as a planar eight membered ring, `S_8`. Reason (R) :`ppi-ppi` bonding is not possible in sulphur.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true
Answer» Correct Answer - D Assertion. Sulphur exists as puckered non planar eight membered ring, `S_8`.

Discussion

124.	Electron affinity of sulphur isA. more than O and SeB. more than O but less than SeC. less than O but more than SeD. equal to O and Se.
Answer» Correct Answer - A Electron affinity of S is more than O and Se.

Discussion

125.	The correct order of electron affinity of B , C , N and O isA. O gt C gt N gt BB. B gt N gt CgtOC. O gt CgtBgtND. O gt Bgt C gt N
Answer» Correct Answer - C Electron affinity of N is zero. This is due to extra stable exactly half filled `p^3` configuration. Except for N and Ne electron affinity increases along the period (2nd period). `therefore` Correct order of electron affinity is O gt B gt C gt N.

Discussion

126.	Sulphuric acid has great affinity for water because itA. It hydrolyses the acidB. It decomposes the acidC. Acid forms hydrates with waterD. Acid decomposes water.
Answer» Correct Answer - C Because it forms hydrate with water.

Discussion

127.	Assertion (A) : In Group 16, oxygen has highest electron affinity. Reason (R ) : Oxygen has the smallest atomic radius in the group.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true
Answer» Correct Answer - B Assertion. In group 16, sulphur has the highest electron affinity. Reason. It is due to relatively compact 2p-subshell in which the electron enters in oxygen.

Discussion

128.	Assertion (A) : When KBr is heated with conc. `H_2SO_4`, HBr is displaced. Reason (R) :HBr is a weaker acid than conc. `H_2SO_4`.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. Both A and R are false
Answer» Correct Answer - D Assertion. When KBr is heated with conc. `H_2SO_4, Br_2` is produced. Reason. Conc. `H_2SO_4` oxidised HBr produced to `Br_2`.

Discussion

129.	Assertion (A) : When KI is heated with conc. `H_2SO_4, I_2` and not HI is produced. Reason (R) :Conc. `H_2SO_4` is a strong oxidising agent and as such oxidises the HI produced.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true
Answer» Correct Answer - A Both assertion (A) and reason (R) are true and R is the correct explanation of A.

Discussion

130.	Assertion (A) : Conc. `H_2SO_4` cannot be used to prepare HI from KI. Reason (R) :Conc. `H_2SO_4` is a strong oxidising agent.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true
Answer» Correct Answer - A Both assertion (A) and reason (R) are true and R is the correct explanation of A.

Discussion

131.	The reason why conc. `H_2SO_4` is used extensively to prepare other acids is that conc. `H_2SO_4` isA. Highly ionisedB. An excellent dehydrating agentC. Has high specific gravityD. Has a high boiling point
Answer» Correct Answer - A As it has high boiling point.

Discussion

132.	When chlorine is bubbled through sodium thiosulphate solution what is formed ?A. `Na_2SO_3`B. `Na_2SO_4` and SC. `Na_2S_4O_6`D. `Na_2S`
Answer» Correct Answer - B `Na_2S_2O_3 + Cl_2 + HOH to Na_2SO_4 + 2HCI + S darr`

Discussion

133.	The reason why conc. `H_2SO_4` is used to prepare other acids like HCl, `HNO_3` etc., is thatA. `H_2SO_4` is a stronger acid than these acidsB. `H_2SO_4` is a strong dehydrating agentC. `H_2SO_4` is a strong oxidising agentD. `H_2SO_4` has a higher boiling point.
Answer» Correct Answer - D `H_2SO_4` with higher boiling point can easily displace, equally strong but volatile acids like HCl, `HNO_3` easily.

Discussion

134.	Acidified solutions of sodium thiosulphate are unstable because in thiosulphateA. The two sulphur atoms are at unstable oxidation state of +2B. The two sulphur atoms are at different oxidation state of +6 and -2C. The S-S bonds are unstableD. Thio compounds contain S in oxidation state of zero.
Answer» Correct Answer - B `Na_2S_2O_3+ HCI to 2NaCl + SO_2 +S+H_2O` Sod. thiosulphate, in the presence of dil. acids decomposes to give `SO_2` and S. This is because S is in +6 and -2 oxidation state in `S_2O_3^(2-)` `.^(-)O-undersetunderset(O)(\|\|)oversetoverset(S)(\|\|)S-O^-` Structure of `S_2O_3^(2-)` ion

Discussion

135.	About `H_2SO_4` which is incorrectA. Reducing agentB. Dehydrating agentC. Sulphonating agentD. Highly viscous
Answer» Correct Answer - A Conc. `H_2SO_4` is highly viscous, it is a dehydrating agent. It can act as a sulphonating agent. However it cannot act as a reducing agent.

Discussion

136.	Sugar becomes black when comes in contact with conc. `H_(2)SO_(4)`. It is because of :A. HydrolysisB. HydrationC. DecolourisationD. Dehydration
Answer» Correct Answer - D `underset("Sugar")(C_12H_22O_11)overset("conc."H_2SO_4)tounderset("Black")(12C)+11H_2O` The process is dehydration

Discussion

137.	In the manufacture of sulphuric acid by contact process, Tyndall box is used toA. convert `SO_2` to `SO_3`B. test the presence of dust particlesC. filter the dust particlesD. remove impurities.
Answer» Correct Answer - C Tyndall box is for testing the presence of dust particles.

Discussion

138.	Sulphur trioxide can be obtained by which of the following reactions:A. `Fe_2(SO_4)_3`B. `S+H_2SO_4`C. `H_2SO_4+PCl_5`D. `CaSO_4 + C`
Answer» Correct Answer - A `HO-underset("Sulphurous acid")underset(OH)underset(\|)overset(ddot)S=F`

Discussion

139.	The reaction of `HCOOH` with `conc. H_2 SO_4` gives :A. COB. `CO_2`C. NOD. `NO_2`
Answer» Correct Answer - A `HCOOH overset("Conc."H_2SO_4)toH_2O+CO`

Discussion

140.	The element evolving two different gases on reaction with `conc. H_2 SO_4`.A. PB. CC. HgD. S
Answer» Correct Answer - B `C+2H_2SO_4overset(Delta)to CO_2(g)+2SO_2(g)+2H_2O`

Discussion

141.	A boy accidently splashes a few drops of `conc. H_2 SO_4` on his cotton shirt and splashed part blackens and holes appears. This is because the sulphuric acidA. dehydrates the cotton with burningB. causes the cotton to react with airC. heat up the cottonD. removes the elements of water from cotton
Answer» Correct Answer - D

Discussion

142.	What is formed when oxalic acid is dehydrated by `conc. H_2 SO_4` ?A. `C+CO_2`B. COC. `CO_2`D. `CO + CO_2`
Answer» Correct Answer - D `underset(COOH)overset(COOH)(\|" " )overset("conc."H_2SO_4//Delta)toCOuarr+CO_2uarr+H_2O`

Discussion

143.	Poison for platinum, a catalyst in contact process of `H_2 SO_4` is ___.A. SulphurB. ArsenicC. SeleniumD. Vanadium
Answer» Correct Answer - B Arsenic (Arsenic oxide) acts as poison for platinum catalyst in contact process for `H_2SO_4` manufacture

Discussion

144.	Which of the following is correct structure of `S_2Cl_2` ?A. B. C. Cl-S-S-ClD. Cl=S=S=Cl
Answer» Correct Answer - B S-S-CI bond is bent due to two lone pairs on S atom

Discussion

145.	`S_2Cl_2` hydrolyses slowly to form HCl, `SO_2` and X. Which of the following is X ?A. `SO_3`B. `H_2`C. `O_2`D. S
Answer» Correct Answer - D `S_2Cl_2 + H_2O to 2HCl + SO_2 +S`

Discussion

146.	Both `CO_2 and SO_2`A. turns lime water milky, however on passing excess of the gas, the solution becomes clearB. are colourlessC. support the combustion of a burning magnesium ribbon.D. turns acidified `K_2Cr_2O_7` solution green.
Answer» Correct Answer - A::B::C Both `SO_2` and `CO_2` turns lime water milky. `Ca(OH)_2(aq)+CO_2(g)to CaCO_3(s)+H_2O(l)` `Ca(OH)_2(aq)+SO_2(g)to CaSO_3(s)+H_2O(l)` On passing excess of the gas, the solutions become clear. `CaCO_3(s)+CO_2(g)+H_2O(l)toCa(HCO_3)_2(aq)` `CaSO_3(s)+SO_2(g)+H_2O(l)toCa(HSO_3)_2(aq)` Both `CO_2` and `SO_2` are colourless gas Both `CO_2` and `SO_2` support the combustion of burning magnesium `CO_2(g)+2Mg(s)to2MgO(s)+C(s)` `SO_2(g)+2Mg(s)to2MgO(s)+S(s)` Only `SO_2` turns `K_2Cr_2O_7//H^(+)` solution green.

Discussion

147.	Bleaching action of `SO_2` is due toA. ReductionB. OxidationC. HydrolysisD. Its acidic nature
Answer» Correct Answer - A

Discussion

148.	Bleaching action of `SO_2` is due to itsA. oxidising propertyB. acidic propertyC. reducing propertyD. basic property
Answer» Correct Answer - C Bleaching action of `SO_2` is due to its reducing property.

Discussion

149.	`H_(2)SO_(4)` has very high corrosive action on skin becauseA. It acts as dehydrating agentB. It reacts with proteinsC. It acts as an oxidising agentD. It acts as dehydrating agent and absorption of water is highly exothermic.
Answer» Correct Answer - D Its corrosive action is due to dehydration of skin.

Discussion

150.	Which of the following has the largest ionic size?A. `F^-`B. `Mg^(2+)`C. `Na^+`D. `O^(2-)`
Answer» Correct Answer - D `Na^(+),Mg^(2+),F^(-) and O^(2-)` are all isoelectronic with 10 electrons each. Nuclear charge on `Na^(+),Mg^(2+) , F^(-) and O^(2-)` are 11,12,9 and 8 respectively. Lesser the nuclear charge, larger is the ion. Thus `O^(2-)` is largest.

Discussion

Explore topic-wise InterviewSolutions in .

The element which shows maximum catenation in Group 16 isA. OB. SC. SeD. Po.

`SO_3` can be obtained byA. `S+H_2SO_4`B. `H_2SO_4 + PCl_5`C. `CaSO_4 +C `D. Heating ferric sulphate

Which has maximum number of oxo groups ?A. `H_2SO_4`B. `H_2SO_3`C. `H_3PO_3`D. `H_3PO_4`

Which of the following is incorrect ?A. `O_2` is weaker oxidant than `O_3`B. `O_2` has larger bond length than `O_3`C. Both `O_2` and `O_3` are paramagneticD. `O_2` is linear and `O_3` is angular in shape.

Which of the following statements regarding sulphur is incorrect?A. The vapour at `200^(@)C` consists mostly of `S_8` ringsB. At `600^(@)C` the gas mainly consists of `S_2` moleculesC. The oxidation state of sulphur is never less than +4 in its compoundsD. `S_2` molecule is paramagnetic.

Which of the following statements regarding sulphur is incorrect?A. `S_2` molecule is paramagneticB. The vapour at `200^(@)C` consists mostly of `S_8` ringC. At `600^(@)C` the gas mainly consists of `S_2` moleculeD. The oxidation state of sulphur is never less than +4 in its compounds.

The element which has a simple cubic lattice in solid state isA. SeB. TeC. PoD. None of these

A group 16 element exists in monoatomic state in the metallic lattice. It also exists in two crystalline forms. The metal isA. PoB. SC. SeD. Te

Which of the following has the largest size?A. `S^(2-)`B. `Se^(2-)`C. `O^(2-)`D. `Te^(2-)`

Which of the following process is used for extraction of sulphur from sulphur beds?A. Acheson processB. Carter processC. Frasch processD. Le-Blanc process.

Which one of the following charrs when warmed with concentrated `H_2SO_4` ?A. CarbohydratesB. ProteinsC. FatsD. Hydrocarbon.

When sulphur is boiled with `Na_(2)SO_(3)` solution, the compound formed isA. Sodium sulphideB. Sodium sulphateC. Sodium persulphateD. Sodium thiosulphate.

Which of the following is not a reducing agent ?A. `SO_2`B. `H_2O`C. `CO_2`D. `NO_2`

Which oxide of sulphur is capable of acting as oxidising as well as reducing agent?A. `SO_3`B. `SO_2`C. `S_2O_3`D. SO.

Which of the following does not exist freely in nature but is a strong reducing agent ?A. `H_2SO_4`B. `H_2SO_3`C. `H_2SO_5`D. `H_2S_2O_8`

Bond angle is minimum forA. `H_2O`B. `H_2S`C. `H_2Se`D. `H_2Te`

`SO_3` when absorbed in 98% `H_2SO_4` it formsA. More concentrated `H_2SO_4 `B. `H_2SO_3`C. `H_2S_2O_8`D. `H_2S_2O_7`

Which form of sulphur exists in the form of zig-zag chains ?A. RhombicB. PlasticC. MonoclinicD. None

Electron affinity of sulphur isA. more than O and SeB. more than O but less than SeC. less than O but more than SeD. equal to O and Se.

The correct order of electron affinity of B , C , N and O isA. O gt C gt N gt BB. B gt N gt CgtOC. O gt CgtBgtND. O gt Bgt C gt N

Sulphuric acid has great affinity for water because itA. It hydrolyses the acidB. It decomposes the acidC. Acid forms hydrates with waterD. Acid decomposes water.

Assertion (A) : When KBr is heated with conc. `H_2SO_4`, HBr is displaced. Reason (R) :HBr is a weaker acid than conc. `H_2SO_4`.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. Both A and R are false

Assertion (A) : Conc. `H_2SO_4` cannot be used to prepare HI from KI. Reason (R) :Conc. `H_2SO_4` is a strong oxidising agent.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true

The reason why conc. `H_2SO_4` is used extensively to prepare other acids is that conc. `H_2SO_4` isA. Highly ionisedB. An excellent dehydrating agentC. Has high specific gravityD. Has a high boiling point

When chlorine is bubbled through sodium thiosulphate solution what is formed ?A. `Na_2SO_3`B. `Na_2SO_4` and SC. `Na_2S_4O_6`D. `Na_2S`

The reason why conc. `H_2SO_4` is used to prepare other acids like HCl, `HNO_3` etc., is thatA. `H_2SO_4` is a stronger acid than these acidsB. `H_2SO_4` is a strong dehydrating agentC. `H_2SO_4` is a strong oxidising agentD. `H_2SO_4` has a higher boiling point.

Acidified solutions of sodium thiosulphate are unstable because in thiosulphateA. The two sulphur atoms are at unstable oxidation state of +2B. The two sulphur atoms are at different oxidation state of +6 and -2C. The S-S bonds are unstableD. Thio compounds contain S in oxidation state of zero.

About `H_2SO_4` which is incorrectA. Reducing agentB. Dehydrating agentC. Sulphonating agentD. Highly viscous

Sugar becomes black when comes in contact with conc. `H_(2)SO_(4)`. It is because of :A. HydrolysisB. HydrationC. DecolourisationD. Dehydration

In the manufacture of sulphuric acid by contact process, Tyndall box is used toA. convert `SO_2` to `SO_3`B. test the presence of dust particlesC. filter the dust particlesD. remove impurities.

Sulphur trioxide can be obtained by which of the following reactions:A. `Fe_2(SO_4)_3`B. `S+H_2SO_4`C. `H_2SO_4+PCl_5`D. `CaSO_4 + C`

The reaction of `HCOOH` with `conc. H_2 SO_4` gives :A. COB. `CO_2`C. NOD. `NO_2`

The element evolving two different gases on reaction with `conc. H_2 SO_4`.A. PB. CC. HgD. S

A boy accidently splashes a few drops of `conc. H_2 SO_4` on his cotton shirt and splashed part blackens and holes appears. This is because the sulphuric acidA. dehydrates the cotton with burningB. causes the cotton to react with airC. heat up the cottonD. removes the elements of water from cotton

What is formed when oxalic acid is dehydrated by `conc. H_2 SO_4` ?A. `C+CO_2`B. COC. `CO_2`D. `CO + CO_2`

Poison for platinum, a catalyst in contact process of `H_2 SO_4` is ___.A. SulphurB. ArsenicC. SeleniumD. Vanadium

Which of the following is correct structure of `S_2Cl_2` ?A. B. C. Cl-S-S-ClD. Cl=S=S=Cl

`S_2Cl_2` hydrolyses slowly to form HCl, `SO_2` and X. Which of the following is X ?A. `SO_3`B. `H_2`C. `O_2`D. S

Both `CO_2 and SO_2`A. turns lime water milky, however on passing excess of the gas, the solution becomes clearB. are colourlessC. support the combustion of a burning magnesium ribbon.D. turns acidified `K_2Cr_2O_7` solution green.

Bleaching action of `SO_2` is due toA. ReductionB. OxidationC. HydrolysisD. Its acidic nature

Bleaching action of `SO_2` is due to itsA. oxidising propertyB. acidic propertyC. reducing propertyD. basic property

`H_(2)SO_(4)` has very high corrosive action on skin becauseA. It acts as dehydrating agentB. It reacts with proteinsC. It acts as an oxidising agentD. It acts as dehydrating agent and absorption of water is highly exothermic.

Which of the following has the largest ionic size?A. `F^-`B. `Mg^(2+)`C. `Na^+`D. `O^(2-)`