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1.

For the reaction `2H_(2)+O_(2)rarr2H_(2)O, DeltaH=-571`. Bond energy of H-H = 435, O=O = 498, then calculate the average bond energy of O-H bond using the above dataA. 484B. `- 484`C. 271D. `- 271`

Answer» Correct Answer - A
`2H_(2)+O_(2)rarr2H_(2)O, DeltaH=-571`
`DeltaH_("reation")=2xxB.E(H_(2))+B.E(O_(2))-2xxB.E.(H_(2)O)`
`therefore -571=(2xx435)+498-2xxB.E. (H_(2)O)`
`or, 2xxB.E(H_(2)O)=870+498+571`
`B.E(H_(2)O)=(1939)/(2)=(969.5)`
`B.E(O-H)=(969.5)/(2)=484.75`.
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