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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
The addition of three masses 1.6 g, 7.32 g and 4.238 g. addressed upto proper decimal places isA. 13.158 gB. 13.2 gC. 13.16 gD. 13.15 g |
| Answer» Correct Answer - 2 | |
| 152. |
The unit of the coefficient of viscosity in S.I. system isA. m/kg-sB. `m-s//kg^2`C. `kg//m-s^2`D. kg/m-s |
| Answer» Correct Answer - 4 | |
| 153. |
The unit of angular acceleration in the SI system isA. `N kg^(-1)`B. `ms^(-2)`C. `rad s^(-2)`D. `m kg^(-1) K` |
| Answer» Correct Answer - 3 | |
| 154. |
Write SI unit of angular momentum: |
| Answer» Correct Answer - kg `m^2 s^(-1)` | |
| 155. |
If A =12.0 cm `pm` 0.1 cm and B 8.5 cm `pm`0.5 cm, find A + B |
| Answer» Correct Answer - `20.5 cm pm 0.6 cm` | |
| 156. |
How many degrees make `pi` rad? |
| Answer» Correct Answer - `180^@` | |
| 157. |
What is the order of magnitude of second in a day ? |
| Answer» Correct Answer - Four | |
| 158. |
How many seconds make one day? |
| Answer» Correct Answer - 86400 s | |
| 159. |
The addition of three masses 1.6 g, 7.32 g and 4.238 g. addressed upto proper decimal places isA. 13.158gB. 13.2gC. 13.16gD. 13.15g |
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Answer» Correct Answer - B |
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| 160. |
Which of the following is not a derived force?A. Tension in a stringB. van der Waal forceC. Nuclear force between proton-protonD. Electrostatic force between proton-proton |
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Answer» Correct Answer - D |
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| 161. |
When a body moves with velocity `V_1` for first half of the journey and `V_2` for remaining half of the journey, its average velocity is given by `2/V_"av"=1/V_1+1/V_2` . If `V_1` and `V_2` are `(15pm0.5)` m/s and `(30pm0.1)` m/s, find the average velocity within error limits. |
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Answer» It is given that `V_"av"=(2V_1V_2)/(V_1+V_2)` First, we shall calculate `V_"av"` `V_"av"=(2xx15xx30)/(15+30)`=20 m/s Now, we shall calculate error in `V_"av"` `2/V_"av"=1/V_1+1/V_2 ` `(2dV_"av")/V_a^2=(dV_1)/V_1^2+(dV_2)/V_2` or `(2dV_"av")/400=0.5/225+0.1/900` `dV_a=0.46` `therefore V_"av"=(20pm0.4)`. |
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| 162. |
Which one of the following does not experience strong nuclear force?A. LeptonsB. BaryonsC. HadronsD. Proton |
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Answer» Correct Answer - A |
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| 163. |
STATEMENT-1 Dimensional constants are the quantities whose values are constant STATEMENT 2 Quantities which are dimensionless are known as dimensional constantsA. Statement-1 is True , Statement-2 is True ,Statement-2 is a correct explanation for Statement-1B. Statement-1 is True , Statement-2 is True ,Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True , Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - 3 | |
| 164. |
For which of the following quantities does ratios are dimensionless? (i) `("work")/("Energy")` (ii) `sintheta` (iii) `(Momentum)/(Time)` |
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Answer» (i)Since work and energy both have the same dimensions `[ML^2T^(-2)]` , their ratio is a dimensionless quantity . (ii)sin(i), Here I represents an angle. An angle is the ratio of two lengths i.e., arc length and radius. Therefore I is dimensionless, hence sin(i) is dimensionless. (iii)`["Momentum"/"Time"]=([MLT^(-1)])/"[T]"` `=[MLT^(-2)]` Hence, the given ratio is not dimensionless. |
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| 165. |
A new system of units is proposed in which unit of mass is `alpha kg,` unit of length `beta` m and unit of time `lambda s.` How much will 5 J measure in this new system ? |
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Answer» We know that dimension of energy = `[ML^(2)T^(-2)]` `"Let "M_(1), L_(1), T_(1) and M_(2), L_(2), T_(2)` are units of mass, length and time in given two systems. `therefore M_(1)=1kg, L_(1)=1m, T_(1)=1s` `M_(2)=alphakg, L_(2)=betam, T_(2)=gammas` The magnitude of a physical quantity remains the same, whatever be the system of units of its measurement i.e.,`" "n_(1)u_(1)=n_(2)u_(2)` `Rightarrow n_(2)=n_(1)(u_(1))/u_(2)=n_(1)([M_(1)L_(1)^(2)T_(1)^(-2)])/([M_(2)L_(2)^(2)T_(2)^(-2)])=5[M_(1)/M_(2)]xx[L_(1)/L_(2)]^(2)xx[T_(1)/T_(2)]^(-2)` `=5[1/alphakg]xx[1/betam]^(2)xx[1/gammas]^(-2)` = `5xx1/alphaxx1/beta^(2)xx1/gamma^(-2)` `n_(2)=(5gamma^(2))/(alphabeta^(2))` Thus, new unit of energy will be `(gamma^(2))/(alphabeta^(2))`. |
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| 166. |
Which of the following practical units of length is not correct?A. 1 fermi = `10^(-15)`mB. 1 astronomical unit = `1.496xx10^(11)`mC. 1 parsec = 3.26 light yearD. 1 light year = `9.46xx10^(12)`m |
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Answer» Correct Answer - D |
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| 167. |
Pick up the dimensionless quantities among the following: (i) Power of a lens ,(ii) Relative density ,(iii) Average velocity ,(iv) Magnification |
| Answer» Relative density , magnification | |
| 168. |
The relative density of lead is 11.3. its density `= ….. g cm^(-3) = …….kg m^(-3)`. Fill in the blanks.A. `1.13xx10^(3)`B. `1.13xx10^(2)`C. `1.13xx10^(4)`D. `11.3` |
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Answer» Correct Answer - C Relative density `=("Density of a substance")/("Density of water")` `therefore`Density of lead `=11.3xx1xx10^(3)kgm^(-3)` (`because`Density of water `=1xx10^(3)" kg "m^(-3)`) `=11.3xx10^(3)" kg "m^(3)=1.13xx10^(4)kg" "m^(-3)` |
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| 169. |
The dimensions of power are _____A. `[M^1L^2 T^(-3)]`B. `[M^2L^1 T^(-2)]`C. `[M^1L^2T^(-1)]`D. `[M^1L^1T^(-2)]` |
| Answer» Correct Answer - 1 | |
| 170. |
if power P and linear mass density are related as `P=alpha/(beta^2+lambda^2)`, then find the dimensions of `alpha` and `beta` |
| Answer» Correct Answer - `[alpha]=[M^3L^0 T^(-3)] , [beta]=[ML^(-1)]` | |
| 171. |
Suppose y represents the work done and x the power, then dimensions of `(d^(2)y)/(dx^(2))` will beA. `[ML^(-1)T^(-2)]`B. `[M^(2)L^(-2)T^(-2)]`C. `[ML^(-1)T^(0)]`D. `[M^(2)L^(-2)T^(-4)]` |
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Answer» Correct Answer - C |
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| 172. |
Dimensions of relative density is |
| Answer» Correct Answer - `[M^0L^0T^0]` | |
| 173. |
Round off the number 970.02 to one decimal place. |
| Answer» Correct Answer - 970 | |
| 174. |
Find the dimensions for electric power. |
| Answer» P = VI Since V Work/Charge, `therefore [P]=["Work"/"Charge"][Current]` or `ML^2 T^(-3)` | |
| 175. |
Two sticks of lengths 12.132 cm and 10.2 cm are placed end to end. Find their total length with due regard to decimal places. |
| Answer» Correct Answer - 22.3 cm | |
| 176. |
The value of `124.2 + 52.487` with due regard to significant places is........A. `176.69`B. `176.7`C. `bar(17)6`D. `177` |
| Answer» Correct Answer - B | |
| 177. |
A book with many printing errors contains four different forumlae for the displacement y of a particle undergoing a certain periodic motion : (i) `y = a sin (2pi t)/(T)` (ii) `y = a sin upsilon t` (iii)`y = (a)/(T) sin (t)/(a)` (iv)`y= (a)/(sqrt2)[sin(2pi t)/(T) + cos (2pi t)/(T)]` Here, a is maximum displacement of particle, `upsilon` is speed of particle, T is time period of motion. Rule out the wrong forumlae on dimensinal grounds.A. `y = A sin (2pi t//T)`B. `y = A sin (Vt)`C. `y = A//T sin(t//A)`D. `y = (A)/(sqrt(2)) (sin omega t + cos omega t)` |
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Answer» Correct Answer - B::C By following dimensional analysis |
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| 178. |
The velocity of a paritcle (v) at an instant t is given by `v=at+bt^(2)`. The dimesion of b isA. [L]B. `[LT^(-1)]`C. `[LT^(-2)]`D. `[LT^(-3)]` |
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Answer» Correct Answer - D `v=at+bt^(2)` `[v]=[bt^(2)]` or `[LT^(-1)]=[bT^(2)]` or `[b]=[LT^(-3)]` |
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| 179. |
Number of particles is given by `n=-D(n_(2)-n_(1))/(x_(2)-x_(1))` crossing a unit area perpendicular to `X`-axis in unit time, where `n_(1)` and `n_(2)` are number of particles per unit volume for the value of `x` meant to `x_(2)` and `x_(1)`. Find dimensions of `D` called as diffusion constantA. `[M^(0)L^(-1)T^(2)]`B. `[M^(0)L^(-1)T^(-1)]`C. `[M^(0)L^(2)T^(-1)]`D. `[M^(0)L^(2)T^(2)]` |
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Answer» Correct Answer - C |
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| 180. |
The number of particles is given by `n = -D(n_(2) - n_(1))/( x_(2) - x_(1))` crossing a unit area perpendicular to X - axis in unit time , where `n_(1)and n_(2)` are particles per unit volume for the value of `x` meant to `x_(2) and x_(1)` . Find the dimensions of `D` called diffusion constant.A. `M^(0) L^(1) T^(2)`B. `M^(0) L^(1) T^(-4)`C. `M^(0) L^(1) T^(-3)`D. `M^(0) L^(2) t^(-1)` |
| Answer» Correct Answer - D | |
| 181. |
The dimensions of potential energy of an object in mass, length and time are respectivelyA. 2,2,1B. 1,2,-2C. `-2,1,2`D. `1,-1,2` |
| Answer» Correct Answer - 2 | |
| 182. |
Which of the following is a dimensional constant?A. MagnificationB. Relative densityC. Gravitational constantD. Relative error |
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Answer» Correct Answer - C |
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| 183. |
Which of the following is not a dimensional constant ?A. MagnificationB. Relative densityC. Gravitational constantD. Relative error |
| Answer» Correct Answer - 3 | |
| 184. |
The exchange particles responsible for weak interactions areA. GluonsB. `pi`-mesonsC. PhotonsD. W and Z bosons |
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Answer» Correct Answer - D |
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| 185. |
Dimensions of solar constant areA. `[M^(0)L^(0)T^(0)]`B. `[MLT^(-2)]`C. `[ML^(2)T^(-2)]`D. `[MT^(-3)]` |
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Answer» Correct Answer - D |
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| 186. |
Solar constant is defined as energy received by Earth per `cm^(2)` per minute. Find the dimensions of solar constant.A. `[M^0L^0T^0]`B. `[MLT^(-2)]`C. `[ML^2T^(-2)]`D. `[M T^(-3)]` |
| Answer» Correct Answer - 4 | |
| 187. |
The amount of heat energy Q, used to heat up a substance depends on its mass m its specific heat capacity (s) and the change in temperature `DeltaT` of the substance. Using dimensional method, find the expression for s is ( Given that `[S]=[L^2 T^(-2)K^(-1)]`) isA. `QmDeltaT`B. `Q/(mDeltaT)`C. `(Qm)/(DeltaT)`D. `(m)/(QDeltaT)` |
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Answer» Correct Answer - B |
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| 188. |
The amount of heat energy Q, used to heat up a substance depends on its mass m its specific heat capacity (s) and the change in temperature `DeltaT` of the substance. Using dimensional method, find the expression for s is ( Given that `[S]=[L^2 T^(-2)K^(-1)]`) isA. `QmDeltaT`B. `Q/(mDeltaT)`C. `"Qm"/(DeltaT)`D. `m/(QDeltaT)` |
| Answer» Correct Answer - 2 | |
| 189. |
Spot out the odd one.A. CalorieB. kilowatt hourC. jouleD. watt |
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Answer» Correct Answer - D Calorie, kilowatt hour, joule all are the units of enegy whereas watt is the unit of power. |
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| 190. |
If n is the numerical value of a physical quantity in the system in which its unit is u. then which of the following relations is correct?A. `n/u`=constantB. `u/n`=constantC. nu=constantD. `n^2u`=constant |
| Answer» Correct Answer - 3 | |
| 191. |
Column II gives some equations. In these equations x is distance, t is time , m is mass, v is velocity u is initial velocity and F is force . Match the statements in Column I to the equations in Column II. |
| Answer» Correct Answer - A(r,s); B(t); C(r,t), D(p,q) | |
| 192. |
Match the column I with column II A. A-p,B-q,C-r,D-sB. A-q,B-p,C-s,D-rC. A-s,B-r,C-q,D-pD. A-r,B-s,C-p,D-q |
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Answer» Correct Answer - C Permittivity of free space `=("Charge"xx"charge")/(4pixx"electrical force"xx"distance"^(2))` `[epsi_(0)]=([AT][AT])/([MLT^(-2)][L]^(2))=[M^(-1)L^(-3)T^(4)A^(2)]` `A-s` Radiant flux `=("energy emitted")/("Time")=([ML^(2)T^(-2)])/([T])=[ML^(2)T^(-3)]` Resistivity`=("Resistance"xx"area")/("Length")` `[rho]=([ML^(2)T^(-3)A^(-2)][L^(2)])/([L])=[ML^(3)T^(-3)A^(-2)]` `C-q` Hubble constant `=("Recession speed")/("Distance")=([LT^(-1)])/([L])=[ML^(0)L^(0)T^(-1)]` |
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| 193. |
Match the entries in column I and column II with same dimensional formula |
| Answer» Correct Answer - A(p,s) , B(q), C(q), D(r,t) | |
| 194. |
Match the column I with column II A. A-q,B-p,C-r,D-sB. A-p,B-q,C_s,D-rC. A-r,B-s,C-p,D-qD. A-s,B-r,C-q,D-p |
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Answer» Correct Answer - C (A) `Pa" "s=[ML^(-1)T^(-2)][T]=[ML^(-1)T^(-1)]` `A-r` ltbr. (B) `N" m "K^(-1)=([MLT^(-2)][L])/([K])=[ML^(2)T^(-2)K^(-1)]` `B-s` (C) `j" kg"^(-1)" "K^(-1)=([ML^(2)T^(-3)])/([M][K])=[M^(0)L^(2)T^(-2)K^(-1)]` `C-p` (D) `W" m"^(-1)" "K^(-1)=([ML^(2)T^(-3)])/([M][K])=[MLT^(-3)K^(-1)]` ltBrgt D-q |
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| 195. |
Assertion: Pressure can not be subtracted from pressure gradient. Reason: Pressure and pressure gradient have different dimensions.A. if both assertion and reason are true reason is the correct explanation of assertion.B. If both assertion and reason are true but reason is not the correct explanation fo assertion.C. If assertion is true but reaso is false.D. IF both assertion and reason are false. |
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Answer» Correct Answer - A Pressure and pressure gradient have different dimension. Hence pressure can not be subtracted from pressure gradient. |
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| 196. |
STATEMENT-1: Velocity gradient has dimensions of frequency STATEMENT-2: Temperature gradient has dimensions of frequency STATEMENT-3: Unit nm is same as unit mN.A. TFFB. TTFC. TFTD. FTT |
| Answer» Correct Answer - 1 | |
| 197. |
If speed of light is `3.00xx10^8` m/s and 1 year =365.25 days, then 1 light year isA. `9.468xx10^15` mB. 9.47 mC. `9.47xx10^5` mD. `9.46xx10^15` m |
| Answer» Correct Answer - 3 | |
| 198. |
`10^(-3)` gram is calledA. kilogramB. milligramC. decigramD. microgram |
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Answer» Correct Answer - B 1 milligram `(mg)=10^(-3)gram(g)` |
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| 199. |
0.205-0.2014 can be expressed asA. `0.0036`B. `3.6xx10^(-3)`C. `4.0xx10^(-3)`D. `4xx10^(-3)` |
| Answer» Correct Answer - 4 | |
| 200. |
In an experiment to measure the diameter of a wire using a screw gauge of resolution 0.001 cm, which of the following may correctly represent the measurement?A. `01.235` cmB. `01.2351` cmC. `01.24` cmD. `0.1.23500` cm |
| Answer» Correct Answer - 1 | |