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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 251. |
A far off planet is estimated to be at a distance D from the earth. If its diametrically opposite extremes subtend an angle `theta` at an observatory situated on the earth, the approximate diameter of the planet isA. `theta/D`B. `D/theta`C. `D theta`D. `1/(D theta)` |
| Answer» Correct Answer - 3 | |
| 252. |
If the average life of a person is taken as 100 s the age of the universe on this scale is of the orderA. `10^10` sB. `10^8` sC. `10^17` sD. `10^9` s |
| Answer» Correct Answer - 1 | |
| 253. |
One unified atomic mass unit represents a mass of magnitudeA. `10^(-30)` kgB. `1.66xx10^27` kgC. `1.66xx10^(-27) ` kgD. `10^30` kg |
| Answer» Correct Answer - 3 | |
| 254. |
Express unified atomic mass unit in kg.A. `1.66xx10^(-25)kg`B. `1.66xx10^(-27)kg`C. `1.66xx10^(-29)kg`D. `1.66xx10^(-31)kg` |
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Answer» Correct Answer - B 1u`=1.66xx10^(-27)kg` |
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| 255. |
Maxwell unifiedA. Electricity with gravitationB. Electricity with magnetismC. Electromagnetism with opticsD. Electromagnetism with weak interaction |
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Answer» Correct Answer - C |
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| 256. |
Match the column I with column II ltBrgt A. A-s,B-r,C-q,D-pB. A-p,B-q,C-r,D-sC. A-q,B-p,C-s,D-rD. A-r,B-s,C-p,D-q |
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Answer» Correct Answer - A Life time of an excited state of an atom `:10^(-8)s` Average human life-span `:10^(9)s` Age of Egyptian pyramids `:10^(11)s` Age of the universe `:10^(17)s` |
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| 257. |
One seond is defined asA. 1650763.73 perods of krypton clockB. 652189.6 peridos of krypton clockC. 1650763.73 periods of cesium clockD. 9192631770 periods of cesium clock. |
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Answer» Correct Answer - D The second is the duration of 9192631770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the cesium-133 atom. |
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| 258. |
The dimensional formula of electric potential isA. `[ML^(2)T^(-3)A^(1)]`B. `[M^(-1)L^(2)T^(-2)A]`C. `[M^(-1)L^(2)T^(-2)A^(-1)]`D. `[ML^(2)T^(-2)A]` |
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Answer» Correct Answer - A Electric potential `V=(W)/(q)=([ML^(2)T^(-2)])/([AT])=[ML^(2)T^(-3)A^(-1)]` |
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| 259. |
Dimensional formula of `DeltaQ`, heat supplied to the system is:A. `[ML^(2)T^(-2)]`B. `[MLT^(-2)]`C. `[ML^(2)T^(-1)]`D. `[MLT^(1)]` |
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Answer» Correct Answer - A Heat supplied to a system is in the form of energy. `therefore` Its diemsnional formula is `[ML^(2)T^(-2)]` |
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| 260. |
The heat generated in a circuit is given by `Q = I^(2) Rt` , where `I` is current , `R` is resistance , and `t` is time . If the percentage errors in measuring `I , R , and t are 2% , 1% , and 1%` , respectively , then the maximum error in measuring heat will beA. `2%`B. `3%`C. `4%`D. `6%` |
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Answer» Correct Answer - D `Q i^(2) Rt, (DeltaQ)/(Q) xx100 = (2Delta i)/(i) xx100 + (Delta R)/(R) xx100 + (Delta t)/(t) xx100` |
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| 261. |
The richardson equaction is given by `I = AT^(2) e^(-B//kT)`. The dimensional formula for `AB^(2)` is same as that for `A` and `B` are constantsA. `IT^(-2)`B. `kT`C. `Ik^(2)`D. `Ik^(2)//T` |
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Answer» Correct Answer - C Here `[A] = IT^(-2)` and `[B] = KT` |
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| 262. |
1 fermi is equla toA. `10^(-12)m`B. `10^(-9)m`C. `10^(-6) A^(0)`D. `10^(-9)` micron |
| Answer» Correct Answer - D | |
| 263. |
The following does not give the unit of energyA. watt secondB. kilowatt hourC. newton metreD. pascal metre |
| Answer» Correct Answer - D | |
| 264. |
The modulus of elasticity is dimesionally equivalent toA. StressB. surface tensionC. StrainD. Coefficient of visocosity |
| Answer» Correct Answer - A | |
| 265. |
If the units of length and force are increased by four times the unit of energy will be incresed byA. `16%`B. `1600%`C. `1500%`D. `400%%` |
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Answer» Correct Answer - C Energy = Force `xx` length |
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| 266. |
If `x` times momentum is work, then the dimensional formula of `x` isA. `[L^(-1)T]`B. `[LT^(-1)]`C. `[ML^(-1) T^(-1)]`D. `[ML^(1) T^(1)]` |
| Answer» Correct Answer - B | |
| 267. |
If the units of mass and velocity are increased by two times then the unit of momentum will be increased by............A. `400%`B. `200 (%)`C. `300%`D. `100%` |
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Answer» Correct Answer - C `P = MV` |
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| 268. |
Torr is the unit of physical quantityA. densityB. pressureC. torqueD. None |
| Answer» Correct Answer - B | |
| 269. |
The mathmatical operation in which the accuracy is limited to least accurate term isA. addtionB. subtractionC. multiplication & divisionD. both 1 and 2 |
| Answer» Correct Answer - D | |
| 270. |
Which of the following is a unit that of force?A. N mB. mNC. nmD. N s |
| Answer» Correct Answer - 2 | |
| 271. |
One snake is equal toA. `10^(-8)s`B. `10^(-9) s`C. `10^(-10) s`D. `10^(9) s` |
| Answer» Correct Answer - A | |
| 272. |
The most accurate reading of the length of a 6.28 cm long fibre isA. 6 cmB. 6.5 cmC. 5.99 cmD. 6.0 cm |
| Answer» Correct Answer - 2 | |
| 273. |
The volume of a cube having sides 1.2 m is appropriately expressed asA. `1.728xx10^6 cm^3`B. `1.7xx10^6 cm^3`C. `1.8xx10^6 cm^3`D. `1.73xx10^6 cm^3` |
| Answer» Correct Answer - 2 | |
| 274. |
Electron volt is the unit ofA. PowerB. Potential differenceC. ChargeD. Energy |
| Answer» Correct Answer - D | |
| 275. |
The most precise reading of the mass of an object among the following isA. 20 gB. 20.0 gC. 20.01 gD. `20xx10^0` g |
| Answer» Correct Answer - 3 | |
| 276. |
When a current of `(2.5 +- 0.5)` ampere flows through a wire, it develops a potential difference of `(20 +- 1)` volt, the resistance of the wire isA. `(8 +- 2) Omega`B. `(10 +- 3) Omega`C. `(18 +- 4) Omega`D. `(20 +- 6) Omega` |
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Answer» Correct Answer - A `R +- Delta R = (V)/(I) + [(DeltaV)/(V) + (Delta I)/(I)] xx100` |
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| 277. |
Ampere second is a unit ofA. CurrentB. ChargeC. EnergyD. Power |
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Answer» Correct Answer - B |
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| 278. |
The dimensions of `gamma` in the relation `v = sqrt((gamma p)/(rho))` (where `v` is velocity, `p` is pressure , `rho` is density)A. DimensionlessB. `[LT^(-1)]`C. `[ML^(-1) T^(-2)]`D. `[ML^(-3)]` |
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Answer» Correct Answer - A `V = sqrt((gamma p)/(rho))` |
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| 279. |
If the unit of length is doubled and that of mass and time is halved, the unit of energy will beA. doubledB. 4 timesC. 8 timesD. same |
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Answer» Correct Answer - C `(E_(2))/(E_(1)) = (M_(2))/(M_(1)) ((L_(2))/(L_(1)))^(2) ((T_(2))/(T_(1)))^(-2)` |
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| 280. |
"Pascal-Second" has dimension ofA. ForceB. EnergyC. PressureD. Coefficient of viscosity |
| Answer» Correct Answer - 4 | |
| 281. |
In a system of units if force (F), acceleration (A) and time (T) are taken as fundamental units, then the dimensional formula of energy will become `[FAT^(x//3)]`. Find value of x? |
| Answer» Correct Answer - 6 | |
| 282. |
If "force" F, "length" L and "time T" are taken as fundamental units , the dimensional formula of mass will beA. `[FL^(-1)T^2]`B. `[FL^(-1)T^(-2)]`C. `[FL^(-1)T^(-1)]`D. `[FL^2 T^2]` |
| Answer» Correct Answer - 1 | |
| 283. |
If force `(F)`, velocity `(V)` and time `(T)` are taken as fundamental units, then the dimensions of mass areA. `[FVT^(-1)]`B. `[FVT^(-2)]`C. `[FV^(-1)T^(-1)]`D. `[FV^(-1)T]` |
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Answer» Correct Answer - D |
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| 284. |
The magnitude of force is `100 N`. What will be its value if the units of mass and time are doubled and that of length is halved?A. `25`B. `100`C. `200`D. `400` |
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Answer» Correct Answer - A `n_(1)[M_(1) L_(1) T_(1)^(-2)] = n_(2) [M_(2)L_(2) T_(2)^(-2)]` |
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| 285. |
If `J` and `E` represent the angualr momentum and rotational kinetic energy of a body, `(J^(2))/(2E)` represents the following physical quantitiy.A. Moment of coupleB. Moment fo forceC. Moment of inertiaD. Force |
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Answer» Correct Answer - C `J rarr ML^(2) T^(-1) , E rarr ML^(2)T^(-2)` |
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| 286. |
A physcial quantity X is related to four measurable quantites a, b, c and d as follows :`X = a^2 b^3 c^(5//2) d^(-2)` The percentage error in the measurement of a, b, c and d are1% , 2%, 3% and 4%, respectively. What is the percentage error in quantity X ? if the value of X calculated on the basis of the above relation is 2.763, to what value should you round off the result ? |
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Answer» Given, physical quantity is `X=a^(2)b^(3)c^(5//2)d^(-2)` Maximum percentage error in X is `(DeltaX)/Xxx100=+-[2((Deltaa)/axx100)+3((Deltab)/bxx100)+5/2((Deltac)/cxx100)+2((Deltad)/d xx100)]` `=+-[2(1)+3(2)+5/2(3)+2(4)]%` `=+-[2+6+15/2+8]=+-23.5%` `therefore" Percentage error in quantity "X=+-23.5%` Mean absolute error in `X=+-0.235=+-0.24` (rounding -off upto significant digits) The calculated value of x should be round-off upto two significant digits. `therefore X=2.8` |
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| 287. |
The accuracy of a clock is one part in `10^(10)`. The maximum difference between two such clocks operating for `10^(10)` secounds is......A. `1s`B. `5s`C. `10s`D. `10^(10)s` |
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Answer» Correct Answer - A `(Delta d)/(d)` |
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| 288. |
A body travels uniformly a distance of `( 13.8 +- 0.2) m` in a time `(4.0 +- 0.3) s`. Find the velocity of the body within error limits and the percentage error.A. `(3.5+-0.6)ms^(-1)`B. `(3.5+-0.3)ms^(-1)`C. `(6.1+-0.6)ms^(-1)`D. `(6.1+-0.3)ms^(-1)` |
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Answer» Correct Answer - B Here, `s=(13.8+-0.2)m,t=(4.0+-0.3)` s `therefore"velocity",v=(s)/(t)=(13.8)/(4.0)=3.45ms^(-1)` (Rounded off to first place of decimal) `therefore(Deltav)/(v)=(Deltas)/(s)+(Deltat)/(t)=(0.2)/(13.8)+(0.3)/(4.0)=(0.8+4.14)/(13.8xx4.0)=(4.94)/(13.8xx4.0)` `=0.0895` or `Deltav=vxx0.0895=3.45xx0.0895=0.3087` `therefore` Velocity `=(3.5+-0.3)ms^(-1)`. |
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| 289. |
The number of singnificant figures in `0.0006032` isA. `7`B. `4`C. `5`D. `2` |
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Answer» Correct Answer - B Use limitation of significant figures. |
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| 290. |
The respective number of significant figures for thenumbers 6.320, 6.032, 0.0006032 areA. 3,4,8B. 4,4,8C. 4,4,4D. 4,3,4 |
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Answer» Correct Answer - C According to the rules of significant figures 6.320 has four significant figures. 6.032 has four significant figurs. 0.0006032 has four significant figures. |
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| 291. |
The number of significant figures in the numbers `4.8000xx10^(4)` and `48000.50` are respectivelyA. 5 and 6B. 5 and 7C. 2 and 7D. 2 and 6 |
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Answer» Correct Answer - B As per rule of significant figures, `4.8000xx10^(4)`has 5 significant figures and 48000.50 has 7 significant figures. |
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| 292. |
Check the dimensional consistency of the following equations : (i) `upsilon = u +at` (ii) `s = ut +(1)/(2) at^2` (iii) `upsilon^2 - u^2 = 2as` |
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Answer» (i)This equation gives the relation for average velocity , `v_"av"` checking the dimensions on both sides. Average velocity `[V_"av"]=[LT^(-1)]to` L.H.S. Initial velocity `[u]=[LT^(-1)] to` R.H.S. Final velocity `[v]=[LT^(-1)]` Since all the terms have the same dimensions , the equation is dimensionally consistent . But it is not correct physically. The correct expression for average velocity for the given case is `v_"av"="u+v"/2` (ii)`s=ut+1/2at^2` [s]=[L] `to` L.H.S. [ut]=[u][t] `=[LT^(-1)][T]` [ut]=[L] `to` R.H.S. `[1/2at^2]=[LT^(-2)][T^2]=[L] to` R.H.S. Each term of the given equation has the same dimensions, namely that of length . Hence, the equation is dimensionally consistent. It is correct physically too. (iii)`v^2-u^2="2s"/a` Checking the dimensions on both sides . `[v^2]=[LT^(-1)][LT^(-1)]` `=[L^(-2)T^(-2)] to `L.H.S. `[u^2]=[LT^(-1)][LT^(-1)]` `=[L^2T^(-2)]` `["2s"/a]=[L]/[LT^(-1)]=[T] to` R.H.S. Dimensions of the quantities on both sides are not same. So the equation is not correct dimensionally, and hence , physically it cannot be correct. |
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| 293. |
The least count of three instruments are 1 mm, 0.1 mm and 0.01 mm. Which one has the greatest precision? |
| Answer» The instrument with least count =0.01 mm | |
| 294. |
The area of a sheet of length 10.2 cm and width 6.8 cm addressed upto proper number of significant figures isA. `69.36cm^(2)`B. `69.4cm^(2)`C. `69cm^(2)`D. `70cm^(2)` |
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Answer» Correct Answer - C |
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| 295. |
The area of a sheet of length 10.2 cm and width 68 cm addressed upto proper number of significant figures isA. `69.26 cm^2`B. `69.4 cm^2`C. `69 cm^2`D. `70 cm^2` |
| Answer» Correct Answer - 3 | |
| 296. |
The radius of a sphere is (2.6 `pm` 0.1) cm The percentage error u iis volume isA. `0.1/2.6xx100%`B. `3xx0.1/2.6xx100%`C. `0.1/(3xx2.6)xx100%`D. `0.1/2.6%` |
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Answer» Correct Answer - B |
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| 297. |
The uncertain digit in the measurement of a length reported as 41.68 cm isA. 4B. 1C. 6D. 8 |
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Answer» Correct Answer - D |
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| 298. |
Taking linear momentum (P), length (L) and time (T) to be fundamental quantities, relate quantities in the columns. |
| Answer» Correct Answer - A(s); B(r) ; C(p) ; D(q) | |
| 299. |
A physical quantity `X` is represented by `X = (M^(x) L^(-y) T^(-z)`. The maximum percantage errors in the measurement of `M , L , and T`, respectively , are `a% , b% and c%`. The maximum percentage error in the measurement of `X` will be |
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Answer» `(Delta x)/(x) xx 100 = a. (Delta M)/(M) xx 100 + b. (Delta L)/(L) xx 100 + c. (Delta T)/(T) xx 100` `= a alpha + b beta + c gamma` |
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| 300. |
The side of a cube is measured by vernier callipers (`10` divisions of a vernier scale coincide with `9` divisions of main scale, where `1` division of main scale is `1mm`). The main scale reads `10mm` and first division of vernier scale coincides with the main scale. Mass of the cube is `2.736 g`. find the density of the cube in appropriate significant figures. |
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Answer» `(" 1 division of main scale")/("Number of divisions in vernier scale") = (1)/(10) = 0.1mm` The side of cube `= 10mm + 1xx 0.1mm = 1.01cm` Now, density `= ("Mass")/("Volume") = (2.736g)/((1.01)^(3) cm^(3)) = 2.66g cm^(-3)` |
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