542 + Interview Questions in WAVE-MOTION IN GENERAL AWARENESS Page 9 InterviewSolution

401.	In a science -friction movie the crew of a ship observes a satellite. Suddenly the satellite blows up. The crew first sees the explosion and after a small time gap hears the sound. Do you think there was a technical lapse?
Answer» Correct Answer - Yes, sound cannot travel in free space.

Discussion

402.	The eqyation of wave is ` x= 5sin ((t)/( 0.4) -( x)/(4))cm ` the maximum velocity of the particles of the medium isA. ` 1m//s `B. ` 1.5m//s`C. `1.25m//s`D. `2m//s`
Answer» Correct Answer - A

Discussion

403.	The equation of sound wave travelling along negative X-direction is given by, ` y= 0.04 sin pi (500t +1.5x)m.`The shortest distance between two particles having phase difference of `pi ` at the same instant isA. 0.66 mB. 0.5 mC. 0.33 mD. 0.2 m
Answer» Correct Answer - A

Discussion

404.	In the above example, find phase difference `DeltaPhi`.(a) of same particle at two different times with interval of 1 s , (b) of two different particle located at a distance of 10cm at same time
Answer» Correct Answer - A::B::D (a) `DeltaPhi=((2pi)/(T))Deltat`, but `(2pi)/(T)=omega=4.0 rad//s` :. `DeltaPhi= omega Deltat=(4.0)(1.0)` `=4rad` `DeltaPhi=((2pi)/(lambda))Deltax`, but `(2pi)/(lambda)=k=0.02cm^-1` :. `DeltaPhi=(0.02)(10)` `=0.2rad`

Discussion

405.	A chord attached to a viberating tunning fork divides it into 6loops, when its tension is 36N. The tensin at which it will viberate in 4loops isA. 24NB. 36NC. 64ND. 81N
Answer» Correct Answer - D

Discussion

406.	A closed organ pipe of length 1.2 m vibrates in its first overtone mode . The pressue variation is maximum atA. 0.8m from the open endB. 0.4m from the open endC. closed endD. 1.0m from the open end
Answer» Correct Answer - B::C

Discussion

407.	Ultrasonic, infrasonic and audio waves travel though a medium with speeds `V_(u), V_(i)` and `V_(a)` respectively then :-A. `v_(a) = v_(i) = a_(a)`B. `v_(u) gt v_(a) gt v_(i)`C. `v_(u) lt v_(a) lt v_(i)`D. `v_(a) lt v_(u) and v_(u) = v_(i)`
Answer» Correct Answer - A

Discussion

408.	A resonance air column shows resonance with a tuning fork of frequency 256 Hz at column lengths 33.4 cmand 101.8 cm. find (i) end-correction and (ii) the speed of sound in air.
Answer» Correct Answer - (i)0.8 cm , (ii)`350.2 ms^(-1)`

Discussion

409.	Which of the following is not the standard from of a sine wave?A. `y=A sin 2pi ((t)/(T)-(x)/(lamda))`B. `y=A sin(vt-kx)`C. `y=A sin omega(t-(x)/(V))`D. `y=A sin k(vt-x)`
Answer» Correct Answer - B

Discussion

410.	A sine wave has an amplitude A and wavelength `lambda`. Let V be the wave velocity and v be the maximum velocity of a particle in the medium. ThenA. V cannot be equal to vB. `V=v`, if `A=lambda/(2pi)`C. `V-v`, if `A=2 pi lambda`D. `V=v`, if `lambda =A/pi`
Answer» Correct Answer - B Let the equation of wave by `y=A sin (omega t-kx)` where, `omega=2pi n` and `k=(2pi)/lambda`. Wave velocity, `V=n lambda =omega /(2pi)xx(2pi)/k=omega/k` Maximum particle velocity `v= A omega` For `V=v, omega/k=A omega` or `A=1/k=lambda/(2pi)`.

Discussion

411.	A sound detector D moves with constant speed on a circle or radius R and centre at O in xy plane. A point source of sound S lines in xy plane at a distance 2R from the point O and emits sound of a given frequnecy . The ratio of maximum frequency recorded by the detector is `11/9` and speed of sound is 340 m/s . the minimum time interval in seconds between reacording a maximum frequency and mimmim frequency is (take R = 17) A. 3B. `pi//3`C. `pi//2`D. `2pi// 3`
Answer» Correct Answer - A

Discussion

412.	sound singal is sent through a compostie tube as shown in the figure. The radius of the semicrcular portion of the tube is r, speed of sound in air is v, the source of sound is capable of giving varied frequencies . If n is an integaer then frequnecy for maximum intensity is given by A. `(nv)/r`B. `(nv)/(t(pi-2))`C. `(nv)/(pir)`D. `(nv) /((r-2 )pi)`
Answer» Correct Answer - B

Discussion

413.	in a sine wave ,postive of different particles at time t=0 is shown in figure. The equation for this wave if it is travelling along postive x -axis can beB A. `y= A sin (omegat - kx)`B. `y=A sin (kx- omegat)`C. `y = A cos (omegat- kx)`D. y= A cos (kx- omega-t)`
Answer» Correct Answer - B

Discussion

414.	A detector is released from rest over a source of sound of frequency `f_(0) = 10^(3) Hz`. The frequency observed by the detector at time t is plotted in the graph. The speed of sound in air is `(g = 10 m // s^(2)`) A. 330m/sB. 350 m/sC. 300 m/sD. 310 m/s
Answer» Correct Answer - C

Discussion

415.	The spectral line emitted by a star, known to have a wavelength of 6500 Å.What is the speed of the star in the line of sight relative to the earth ? Is the star approaching or receding ? Speed of light in air`=3xx10^(8) ms^(-1)`.
Answer» Correct Answer - `1.15xx10^(6) ms^(-1)`, receding

Discussion

416.	Predict for the wave `y = A cos.(2pix)/(lambda) sin ((2pivt)/(lambda))`A. It is a progressive waveB. It is a transverse progressive waveC. It is a longitudinal progressive waveD. It is a stationary wave
Answer» Correct Answer - D

Discussion

417.	A `200 Hz` wave with amplitude `1 mm` travels on a long string of linear mass density `6 g//m` keep under a tension of `60 N`. (a) Find the average power transmitted across a given point on the string. (b) Find the total energy associated with the wave in a `2.0 m` long portion of the string.
Answer» Correct Answer - A::B::D (a) As derived in above problem, power `=2pi^(2)f^(2)A^(2) sqrt(Tmu)` `=(2) (pi)^(2)(200)^(2)(10^(-3))^(2)`sqrt(60xx(0.006))` `=0.47 W` (b) Energy density, `u =(1)/(2)rhoomega^(2)A^(2)` Total energy `=(u)(V)` `=((1)/(2)rhoomega^(2)A^(2)) (IS)` But, `rhoS = mu` `:.` Total energy `=(1)/(2)mul(2pif)^(2)A^(2)` `=2pi^(2)f^(2)A^(2)mul` `=(2)(pi)^(2)(200)^(2)(10^(-3))^(2)(0.006)(2.0)` `=9.4 xx 10^(-3)J= 9.4 mJ`

Discussion

418.	The equation of a longitudinal stationary wave produced in a closed organ pipe is `y=6 sin (2pix)/(6) cos 160 pi t` where x, y are in cm and t in second.Find (i)the frequency , amplitude and wavelength of the original progressive wave (ii)separation between two successive nodes and (iii)equation of the original progressive wave.
Answer» Correct Answer - (i)v=80 Hz, a=3 cm, `lambda=6 cm` , (ii)`y=3 sin (pi/3 x-160 pi t)`

Discussion

419.	A certain `120 Hz` wave on a string has an amplitude of `0.160 mm`. How much energy exits in an`80 g` length of the string?
Answer» Energy density,`u = (1)/(2)rho omega^(2)A^(2)` Total energy `=(u) (V) ` `=(1)/(2)(rhoV)(2pif)^(2)A^(2)` `=2pi^(2) mf^(2) A^(2)` `=(2) (pi)^(2) (0.08)(120)^(2)(0.16 xx10^(-3))^(2)` `=581xx 10^(-3)J` `=0.58mJ`

Discussion

420.	The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is `90^(@)` . Then the velocity of wave will beA. 144 m/sB. 256 m/sC. 384 m/sD. 720 m/s
Answer» Correct Answer - A

Discussion

421.	A string consists of two parts attached at x=0 , The right part of the string `(xlt 0)` has mass per unit length `mu_r` and the left part of the string ` (xlt 0)` has mass per unit length ` mu _l` The tension in the string is T. If a wave of units amplitude travels along the left part of the string,what is the amplitude of the wave that is transmitted to the right part of the string?A. ` 1`B. ` (2)/( 1+sqrt (mu _l //mu _y))`C. ` (2)/( 1+sqrt (mu _l //mu _y))`D. ` (sqrt( mu_l //mu_y)-1)/( sqrt(mu_l //mu_y )+ 1)`
Answer» Correct Answer - A

Discussion

422.	A 10 W source of sound of frequency 1000 Hz sends out wave in air. The displacment amplitude a distance of 10 m from the source is (speed of sound in air = 340 m/s and density of air = 129 `kg/m^(3)`)A. 0.62 `mum`B. `4.2 mu m`C. `1.6 mu m `D. `0.96 mu m`
Answer» Correct Answer - D

Discussion

423.	If the maximum particle velocity is 4 times of the wave velocity then relation between wavelength and amplitude isA. ` lambda =(A)/( 2pi ) `B. ` lambda = (pi)/(2A) `C. ` lambda =(piA)/(2) `D. ` lambda =(piA) /(3) `
Answer» Correct Answer - C

Discussion

424.	Assertion: If two waves of same amplitude produce a resultant wave of same amplitude,then the phase difference between them will be ` 120 ^(@) ` Reason: The resultant amplitude of two waves is equal to vector sum of amplitudes treated as vectorsA. Assertion is True ,Reason is True , Reason is a correct explanation for AssertionB. Assertion is True Reason is True : Reason is not a correct explanation for AssertionC. Assertion is True ,Reason is FalseD. Assertion is False but , Reason is True
Answer» Correct Answer - C

Discussion

425.	If the amplitude of a wave at a distance `r` from a point source is `A`, the amplitude at a distance `2 r` will beA. AB. 2AC. `A//2`D. `A//4`
Answer» Correct Answer - C Intensity = Energy/Sec/Area = Power/Area. From a point source, energy spreads over the surface of a sphere of radius r. `:.` Intensity `=P/A=P/(4pi r^(2)) prop 1/r^(2)` But intensity = `("Amplitude")^(2)` `:. ("Amplitude")^(2) prop 1/r^(2)` or Amplitude `prop 1/r` At distance 2r, amplitude becomes `A//2`

Discussion

426.	The equation of a progresive wave along a string is `y=2 x 10^(-6) sin pi (t/0.002-x/60)` where x is in cm and t is in second. What is the phase difference at any instant between two points which are 2 cm apart?A. `pi/2` radianB. `pi/15` radianC. `pi/20` radianD. `pi/30` radian
Answer» Correct Answer - D `y=2 xx10^(-6) sin 2pi [t/0.004-f/120]` Comparing with `y=A sin 2pi (t/T-x/lambda)` We get, `lambda=120` cm `:.` Phase difference `=(2pi x)/lambda =(2pi)/120xx2=pi/30` rad

Discussion

427.	A closed organ pipe and an open organ pie of same length produce four bets in their fundamental mode when sounded together, If length of the open organ pipe is increased, then the number of beats willA. increaseB. decreaseC. remain constantD. may increase or decrease
Answer» Correct Answer - D

Discussion

428.	An open organ pipe of length l is sounded together with another open organ pipe of length l + x in their fundamental tones. Speed of sound in air is v. the beat frequency heard will be (`x lt lt l`)A. `(vx)/(4//^(2))`B. `(vl^(2))/(2x)`C. `(vl)/(2//^(2))`D. `(vl^(2))/(2l)`
Answer» Correct Answer - C

Discussion

429.	When a sound wave goes from one medium to another, the quantity that remains unchanged is :A. wavelengthB. velocityC. frequencyD. propagation constant
Answer» Correct Answer - C

Discussion

430.	At room temperature the ratio of velocity of sound in air at 10 atmospheric pressure to the at 1 atmospheric pressure will beA. `sqrt10 : 1`B. `1 : sqrt10`C. `1 : 1`D. `3 : 2`
Answer» Correct Answer - C Velocity of sound is independent of atmospheric pressure

Discussion

431.	The velocity of sound in air is affected by change in the (i) atmospheric pressure (ii) moisture content of air (iii) temperature of air (iv) composition of air.A. moisture content of airB. atmospheric pressureC. temperature of airD. composition of air
Answer» Correct Answer - B

Discussion

432.	At `10^5 Nm^(-2)` atmospheric pressure the density of air is `1.29 kg m^(-3)`.If `gamma=1.41` for air, calculate the speed of sound in air.
Answer» Correct Answer - `330.6 ms^(-1)`

Discussion

433.	An open organ pipe is vibrating in its fifth overtone. The distance between two consecutive pionts where pressure amlitude is `1/sqrt 2` times pressure amplitude at pressure antinodes,is 40 cm , then the length of open organ pipe is ( neglect end connection )A. 3 cmB. 3.6 cmC. 4.2 cmD. 4.8 cm
Answer» Correct Answer - C

Discussion

434.	A metallic bar clamped at its middle point vibrates with a frequency v when it is rubbed at one end. If its length is doubled, what will be its natural frequency of vibration ?
Answer» Correct Answer - v/2

Discussion

435.	At normal temperature and pressur, 4g of He occupies a volume of 22.4 litre. Determine the speed of sound in helium. Take 1 atmospheric pressure `=10^(5)N//m^(2)` and `gamma` for helium `=1.67`.
Answer» Correct Answer - `967 ms^(-1)`

Discussion

436.	An open organ pipe produces a note of frequency 512 Hz at `15^@ C`, calculate the length of the pipe.Velocity of sound at `0^@C` is `335 ms^(-1)`.
Answer» Correct Answer - 0.336 m

Discussion

437.	The prongs of a tuning fork A originally in unison with a fork B os frequency `312` are filed and the forks produce `5` beats per second when sounded together. What is the pitch of A after filing?
Answer» Correct Answer - `317`

Discussion

438.	A sonometer wire is in unison with a tuning fork . When its length increases by 4% , it gives 8 beats/with the same fork. What is the frequency of the fork ?A. 196 HzB. 200 HzC. 204 HzD. 208 Hz
Answer» Correct Answer - B `(Deltan)/(n) = (Deltal)/(l_(2))` `(8)/(n) = (4)/(104)` `n = 2 xx 104 = 208 Hz`

Discussion

439.	Two organ pipes at `16^@C` produces 40 beats in 2.5 seconds. What happens when temperature rises to `40^@C` ? Coefficients of linear expansion of the pipes are negligible.
Answer» Correct Answer - 16.65 beats/s are produced

Discussion

440.	A source of frequency 10kHz when viberted over than mouth of a closed organ is in unison at 300K. The beats produced when temperature rises by 1KA. 30HzB. 13.33HzC. 16.67HzD. 40Hz
Answer» Correct Answer - C

Discussion

441.	A closed organ pipe and an pipe of same length produce 4 beats when they are set into vibration simultaneoulsy. If the length of each of them were twice their initial lengths. The number of beats produced will be [Assume same mode of viberation in both cases]A. 2B. 4C. 1D. 8
Answer» Correct Answer - A

Discussion

442.	If the frequency of two sources of sound are 512 Hz and 516 Hz then the time interval between two consecutive beats produced by sounding them together will beA. 0.5 sB. 0.125 sC. 0.25 sD. 4s
Answer» Correct Answer - C `n = n_(2) - n_(1) = 516 - 512 = 4` `T = (1)/(n) = (1)/(4)s`

Discussion

443.	Write the equation of a wave identical to the wave represented by the equation `y=5sinpi(4.0t-0.02x)`, but moving in opposite direction. Write the equation of stationary wave produced by the combination of these two waves. Determine the distance between two nearest nodes. All distances in the equations are in mm.
Answer» Correct Answer - (i)`y=5 sin pi (4.0 t+0.02 x)` , (ii)`y=10 cos 0.02 pi x sin 4.0 pi t, 50 mm`

Discussion

444.	Fundamental frequency of a closed of a pipe is 100 and that of an open pipe is 200 Hz. Match following `(V_(s) = 330m//s)`
Answer» Correct Answer - (a)P, (b)P, (c )S

Discussion

445.	A sound source of frequency 500 Hz is producing longitudinal waves in a spring.The distance between two consecutive rarefractions is 24 cm.If the amplitude of vibration of a particle of the spring is 3.0 cm and the wave is travelling in the negative x-direction, then write the equation for the wave.Assume that the source is at x=0 and at this point the displacement is zero at the time t=0.
Answer» Correct Answer - `y=3.0 sin 2pi (25 t-x//24)`

Discussion

446.	Audible range of frequencies to which human car responds varies between 20 to 20,000 Hz.Express the range in terms of (i)wavelength in air and (ii)time period . The speed of sound in air is `350 ms^(-1)`.
Answer» Correct Answer - (i)`1.75xx10^(-2)` m to 17.5 m , (ii)`5xx10^(-5)` s to `5xx10^(-2)` s

Discussion

447.	The equation of a transverse wave travelling along a coil spring is `y=4.0 sin pi (0.010 x-2.0t)` where y and x are in cm and t in s. Find the (i)amplitude (ii)wavelength (iii)initial phase at the origin (iv)speed and (v)frequency on the wave.
Answer» Correct Answer - (i)`4.0xx10^(-2)m ` , (ii)2.0 m , (iii)0 , (iv)`2.0 ms^(-1)` , (v)`1.0 s^(-1)`

Discussion

448.	Speed of sound in air is `330m//s`.Find maximum and minimum wavelength of audible sound in air.
Answer» Correct Answer - A::B Frequency of audible sound varies from `20Hz` to `20000Hz`. Speed of all frequencies in air will be same `(=330m//s)` `:.lambda_min=(v)/(f_(max))=330/20000` `=0.0165m` Similarly, `lambda_max=(v)/(f_(min))=330/20` =`16.5m`

Discussion

449.	Phenomenon of beats is audible if the difference in the frequency of the sound waves isA. very largeB. zeroC. more than 20D. less than 20
Answer» Correct Answer - D

Discussion

450.	The path difference between the two waves `y_(1)=a_(1) sin(omega t-(2pi x)/(lambda)) and y(2)=a_(2) cos(omega t-(2pi x)/(lambda)+phi)` isA. `lambda/(2pi) (phi)`B. `lambda/(2pi) (phi+pi/2)`C. `(2pi)/lambda (phi-pi/2)`D. `(2pi)/lambda (phi)`
Answer» Correct Answer - B As `y_(2)=a_(2) cos (omega t-(2pi x)/lambda +phi)` `=a_(2) sin [pi/2+(omega t-(2pi x)/lambda +phi)]` Compare it with `y_(1)=a_(1) sin (omega t-(2pi x)/lambda)` Phase difference `=(pi/2 +phi)` `:.` Path difference `=lambda/(2pi)(pi/2 +phi)`.

Discussion

Explore topic-wise InterviewSolutions in .

In a science -friction movie the crew of a ship observes a satellite. Suddenly the satellite blows up. The crew first sees the explosion and after a small time gap hears the sound. Do you think there was a technical lapse?

The eqyation of wave is ` x= 5sin ((t)/( 0.4) -( x)/(4))cm ` the maximum velocity of the particles of the medium isA. ` 1m//s `B. ` 1.5m//s`C. `1.25m//s`D. `2m//s`

The equation of sound wave travelling along negative X-direction is given by, ` y= 0.04 sin pi (500t +1.5x)m.`The shortest distance between two particles having phase difference of `pi ` at the same instant isA. 0.66 mB. 0.5 mC. 0.33 mD. 0.2 m

In the above example, find phase difference `DeltaPhi`.(a) of same particle at two different times with interval of 1 s , (b) of two different particle located at a distance of 10cm at same time

A chord attached to a viberating tunning fork divides it into 6loops, when its tension is 36N. The tensin at which it will viberate in 4loops isA. 24NB. 36NC. 64ND. 81N

A closed organ pipe of length 1.2 m vibrates in its first overtone mode . The pressue variation is maximum atA. 0.8m from the open endB. 0.4m from the open endC. closed endD. 1.0m from the open end

Ultrasonic, infrasonic and audio waves travel though a medium with speeds `V_(u), V_(i)` and `V_(a)` respectively then :-A. `v_(a) = v_(i) = a_(a)`B. `v_(u) gt v_(a) gt v_(i)`C. `v_(u) lt v_(a) lt v_(i)`D. `v_(a) lt v_(u) and v_(u) = v_(i)`

A resonance air column shows resonance with a tuning fork of frequency 256 Hz at column lengths 33.4 cmand 101.8 cm. find (i) end-correction and (ii) the speed of sound in air.

Which of the following is not the standard from of a sine wave?A. `y=A sin 2pi ((t)/(T)-(x)/(lamda))`B. `y=A sin(vt-kx)`C. `y=A sin omega(t-(x)/(V))`D. `y=A sin k(vt-x)`

A sine wave has an amplitude A and wavelength `lambda`. Let V be the wave velocity and v be the maximum velocity of a particle in the medium. ThenA. V cannot be equal to vB. `V=v`, if `A=lambda/(2pi)`C. `V-v`, if `A=2 pi lambda`D. `V=v`, if `lambda =A/pi`

in a sine wave ,postive of different particles at time t=0 is shown in figure. The equation for this wave if it is travelling along postive x -axis can beB A. `y= A sin (omegat - kx)`B. `y=A sin (kx- omegat)`C. `y = A cos (omegat- kx)`D. y= A cos (kx- omega-t)`

A detector is released from rest over a source of sound of frequency `f_(0) = 10^(3) Hz`. The frequency observed by the detector at time t is plotted in the graph. The speed of sound in air is `(g = 10 m // s^(2)`) A. 330m/sB. 350 m/sC. 300 m/sD. 310 m/s

The spectral line emitted by a star, known to have a wavelength of 6500 Å.What is the speed of the star in the line of sight relative to the earth ? Is the star approaching or receding ? Speed of light in air`=3xx10^(8) ms^(-1)`.

Predict for the wave `y = A cos.(2pix)/(lambda) sin ((2pivt)/(lambda))`A. It is a progressive waveB. It is a transverse progressive waveC. It is a longitudinal progressive waveD. It is a stationary wave

A `200 Hz` wave with amplitude `1 mm` travels on a long string of linear mass density `6 g//m` keep under a tension of `60 N`. (a) Find the average power transmitted across a given point on the string. (b) Find the total energy associated with the wave in a `2.0 m` long portion of the string.

A certain `120 Hz` wave on a string has an amplitude of `0.160 mm`. How much energy exits in an`80 g` length of the string?

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is `90^(@)` . Then the velocity of wave will beA. 144 m/sB. 256 m/sC. 384 m/sD. 720 m/s

A 10 W source of sound of frequency 1000 Hz sends out wave in air. The displacment amplitude a distance of 10 m from the source is (speed of sound in air = 340 m/s and density of air = 129 `kg/m^(3)`)A. 0.62 `mum`B. `4.2 mu m`C. `1.6 mu m `D. `0.96 mu m`

If the maximum particle velocity is 4 times of the wave velocity then relation between wavelength and amplitude isA. ` lambda =(A)/( 2pi ) `B. ` lambda = (pi)/(2A) `C. ` lambda =(piA)/(2) `D. ` lambda =(piA) /(3) `

If the amplitude of a wave at a distance `r` from a point source is `A`, the amplitude at a distance `2 r` will beA. AB. 2AC. `A//2`D. `A//4`

The equation of a progresive wave along a string is `y=2 x 10^(-6) sin pi (t/0.002-x/60)` where x is in cm and t is in second. What is the phase difference at any instant between two points which are 2 cm apart?A. `pi/2` radianB. `pi/15` radianC. `pi/20` radianD. `pi/30` radian

A closed organ pipe and an open organ pie of same length produce four bets in their fundamental mode when sounded together, If length of the open organ pipe is increased, then the number of beats willA. increaseB. decreaseC. remain constantD. may increase or decrease

An open organ pipe of length l is sounded together with another open organ pipe of length l + x in their fundamental tones. Speed of sound in air is v. the beat frequency heard will be (`x lt lt l`)A. `(vx)/(4//^(2))`B. `(vl^(2))/(2x)`C. `(vl)/(2//^(2))`D. `(vl^(2))/(2l)`

When a sound wave goes from one medium to another, the quantity that remains unchanged is :A. wavelengthB. velocityC. frequencyD. propagation constant

At room temperature the ratio of velocity of sound in air at 10 atmospheric pressure to the at 1 atmospheric pressure will beA. `sqrt10 : 1`B. `1 : sqrt10`C. `1 : 1`D. `3 : 2`

The velocity of sound in air is affected by change in the (i) atmospheric pressure (ii) moisture content of air (iii) temperature of air (iv) composition of air.A. moisture content of airB. atmospheric pressureC. temperature of airD. composition of air

At `10^5 Nm^(-2)` atmospheric pressure the density of air is `1.29 kg m^(-3)`.If `gamma=1.41` for air, calculate the speed of sound in air.

An open organ pipe is vibrating in its fifth overtone. The distance between two consecutive pionts where pressure amlitude is `1/sqrt 2` times pressure amplitude at pressure antinodes,is 40 cm , then the length of open organ pipe is ( neglect end connection )A. 3 cmB. 3.6 cmC. 4.2 cmD. 4.8 cm

A metallic bar clamped at its middle point vibrates with a frequency v when it is rubbed at one end. If its length is doubled, what will be its natural frequency of vibration ?

At normal temperature and pressur, 4g of He occupies a volume of 22.4 litre. Determine the speed of sound in helium. Take 1 atmospheric pressure `=10^(5)N//m^(2)` and `gamma` for helium `=1.67`.

An open organ pipe produces a note of frequency 512 Hz at `15^@ C`, calculate the length of the pipe.Velocity of sound at `0^@C` is `335 ms^(-1)`.

The prongs of a tuning fork A originally in unison with a fork B os frequency `312` are filed and the forks produce `5` beats per second when sounded together. What is the pitch of A after filing?

A sonometer wire is in unison with a tuning fork . When its length increases by 4% , it gives 8 beats/with the same fork. What is the frequency of the fork ?A. 196 HzB. 200 HzC. 204 HzD. 208 Hz

Two organ pipes at `16^@C` produces 40 beats in 2.5 seconds. What happens when temperature rises to `40^@C` ? Coefficients of linear expansion of the pipes are negligible.

A source of frequency 10kHz when viberted over than mouth of a closed organ is in unison at 300K. The beats produced when temperature rises by 1KA. 30HzB. 13.33HzC. 16.67HzD. 40Hz

A closed organ pipe and an pipe of same length produce 4 beats when they are set into vibration simultaneoulsy. If the length of each of them were twice their initial lengths. The number of beats produced will be [Assume same mode of viberation in both cases]A. 2B. 4C. 1D. 8

If the frequency of two sources of sound are 512 Hz and 516 Hz then the time interval between two consecutive beats produced by sounding them together will beA. 0.5 sB. 0.125 sC. 0.25 sD. 4s

Fundamental frequency of a closed of a pipe is 100 and that of an open pipe is 200 Hz. Match following `(V_(s) = 330m//s)`

Audible range of frequencies to which human car responds varies between 20 to 20,000 Hz.Express the range in terms of (i)wavelength in air and (ii)time period . The speed of sound in air is `350 ms^(-1)`.

The equation of a transverse wave travelling along a coil spring is `y=4.0 sin pi (0.010 x-2.0t)` where y and x are in cm and t in s. Find the (i)amplitude (ii)wavelength (iii)initial phase at the origin (iv)speed and (v)frequency on the wave.

Speed of sound in air is `330m//s`.Find maximum and minimum wavelength of audible sound in air.

Phenomenon of beats is audible if the difference in the frequency of the sound waves isA. very largeB. zeroC. more than 20D. less than 20

The path difference between the two waves `y_(1)=a_(1) sin(omega t-(2pi x)/(lambda)) and y(2)=a_(2) cos(omega t-(2pi x)/(lambda)+phi)` isA. `lambda/(2pi) (phi)`B. `lambda/(2pi) (phi+pi/2)`C. `(2pi)/lambda (phi-pi/2)`D. `(2pi)/lambda (phi)`