Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

The energy possessed by an object because of its motion is termed _____(a) potential energy(b) kinetic energy(c) nuclear energy(d) solar energyI have been asked this question in semester exam.I'm obligated to ask this question of Various Forms of Energy : The Law of Conservation of Energy topic in section Work, Energy and Power of Physics – Class 11

Answer»

Right choice is (B) kinetic ENERGY

For explanation: An object in motion possesses a velocity “V” at any instant of time.

This energy is termed “kinetic energy” and is given by;

Kinetic Energy = 1/2 x m x v^2

where;

m = Mass of the object in motion

2.

Since the potential energy of an object depends on the acceleration due to gravity and since the acceleration due to gravity decreases as altitude increases, we can conclude that the potential energy of an object decreases as altitude increases.(a) True(b) FalseI got this question by my college professor while I was bunking the class.My doubt is from Potential Energy in division Work, Energy and Power of Physics – Class 11

Answer» CORRECT answer is (B) False

The explanation is: The potential energy of an object does not DEPEND on acceleration due to gravity at the instantaneous position of the object but depends on the acceleration due to gravity at the reference point (such as the surface of the earth). Hence, potential energy increases as altitude increases.
3.

Which of the following statements are true?(a) Energy can be created and destroyed(b) Energy cannot be created but only destroyed(c) Energy cannot be destroyed but only created(d) Energy can neither be created nor destroyedI got this question by my college director while I was bunking the class.I want to ask this question from Various Forms of Energy : The Law of Conservation of Energy in portion Work, Energy and Power of Physics – Class 11

Answer»

Correct answer is (d) ENERGY can neither be created nor destroyed

To explain I would say: According to the law of conservation of energy, energy can neither be created nor destroyed but can only be changed from ONE form to another. This is ALSO one of the fundamental concepts of thermodynamics.

4.

A force of 40 N acts on body of mass 5 Kg. What is the amount of work done if the total displacement is 2 m and is in the direction of the force applied?(a) 80 J(b) -80 J(c) 40 J(d) 16 JThe question was posed to me by my school teacher while I was bunking the class.My question is taken from Work in section Work, Energy and Power of Physics – Class 11

Answer»

The correct choice is (a) 80 J

Best explanation: The work done on a body is OBTAINED by CALCULATING the dot product of the force and DISPLACEMENT vector. Since the displacement is in the direction of the applied force, the work done is positive and is equal to 80 J.

5.

The work done by a body while covering a vertical height of 5m is 50 kJ. By how much amount has the energy of the body changed?(a) 50 kJ(b) -50 kJ(c) 25 kJ(d) 10 kJThis question was addressed to me by my school principal while I was bunking the class.I need to ask this question from Work-Energy Theorem topic in portion Work, Energy and Power of Physics – Class 11

Answer»

Correct OPTION is (a) 50 kJ

Explanation: The work done by the body is 50 kJ. Hence by the work-energy theorem, we can SAY that the TOTAL change in energy is equal to the total work done. THEREFORE, the total change in energy is 50 kJ. Since only the ‘amount’ has been asked, the sign, which DENOTES the direction of energy transfer, does not matter.

6.

The energy possessed by a body by the virtue of its motion is called ______(a) Kinetic energy(b) Potential energy(c) Total energy(d) Motion energyI got this question in semester exam.I'm obligated to ask this question of Introduction to Work, Energy and Power topic in portion Work, Energy and Power of Physics – Class 11

Answer» RIGHT CHOICE is (a) Kinetic energy

To explain: The kinetic energy of a body emerges due to its motion. More specifically, the VELOCITY of a body decides the AMOUNT of kinetic energy it has. Usually, the kinetic energy of a body with mass m is given as K.E. = \(\Big(\frac{1}{2}\Big)\)mv^2, where V is the velocity of the body.
7.

A motor is used to pump water from a depth of 5 m to fill a volume of 10 cubic meters in 5 minutes. If 50% of the power is wasted, what is the power of the motor? (Assume g = 10m/s^2)(a) 1000/3 W(b) 3000/3 W(c) 5000/3 W(d) 10000/3 WI got this question in exam.The doubt is from Power topic in portion Work, Energy and Power of Physics – Class 11

Answer»

The CORRECT answer is (d) 10000/3 W

Easy EXPLANATION: Density of WATER = 1000 kg/m^3

Mass of water in 10m^3 = 1000 x 10

 = 10,000 kg

Volume of water filled in 1s = 10/(5×60)

 = 1/30 m^3

Mass filled in 1s = 1/30 x 1000

 = 100/3 kg

Power = 100/3 x 10 x 5; [g = 10m/s^2]

 = 5000/3 W

Since 50% of power is wasted, power of motor = 5000/3 x 2

 = 10000/3 W.

8.

The law of conservation of energy is not applicable to mechanical systems as they require energy input to keep working.(a) True(b) FalseThe question was posed to me in class test.This intriguing question originated from Various Forms of Energy : The Law of Conservation of Energy in division Work, Energy and Power of Physics – Class 11

Answer» CORRECT CHOICE is (b) False

The explanation is: The law of conservation of energy is APPLICABLE to mechanical SYSTEMS but it may not NECESSARILY be applicable to a “machine” that requires constant power input to operate because it would then essentially be an open system.
9.

The potential energy possessed by a spring is also known as _____(a) Elastic potential energy(b) Extensive potential energy(c) Compressive potential energy(d) Deflection potential energyThis question was addressed to me during an internship interview.My question is taken from The Potential Energy of a Spring in chapter Work, Energy and Power of Physics – Class 11

Answer»

Right choice is (a) Elastic potential energy

To explain I would say: The potential energy stored in a SPRING is the CONSEQUENCE of its elastic PROPERTY and hence it is also TERMED “elastic potential energy”. It can be stored when the spring is extended or compressed.

10.

If a solid sphere of mass 200g and radius 20cm is rotating with an angular velocity of 5 rad s^-1, its rotational kinetic energy is _____(a) 0.06J(b) 0.04J(c) 0.03J(d) 0.004JThis question was addressed to me in exam.This intriguing question originated from Kinetic Energy in portion Work, Energy and Power of Physics – Class 11

Answer»

Right option is (b) 0.04J

The explanation is: Rotational kinetic ENERGY is given by 0.5*I*Ω^2. I of a solid SPHERE is given by (2/5)*m*r². So, rotational kinetic energy is 0.5*0.4*(200/1000)*(20/100)^2*5^2 = 0.04J.

11.

What is the value of spring constant if force of 200 N is acting on it and the spring is compressed by 2m?(a) 100 kgs^-2(b) 100 kgs^-1(c) 100 kg^2s^2(d) 100 KgsI got this question in class test.My question is from Work Done by a Variable Force in division Work, Energy and Power of Physics – Class 11

Answer»

The correct option is (a) 100 kgs^-2

Best EXPLANATION: FORCE on a elongated/compressed spring is GIVEN by F = k*x where k is spring constant and x is elongation/compression. So, 200 = k*2 which gives k = 100 kgs^-2.

12.

A particle of mass 200g is thrown vertically upwards with a speed of 10ms^-1, the work done by force of gravity while the particle goes up is given by _____(a) 0.5J(b) 5J(c) 10J(d) 15JThis question was addressed to me in an interview for job.I'd like to ask this question from Kinetic Energy topic in portion Work, Energy and Power of Physics – Class 11

Answer»

Correct OPTION is (c) 10J

Easy explanation: The maximum height ATTAINED by particle is given by u^2/(2*G). So total work done would be gain in POTENTIAL energy i.e. m*g*h = m*g*(u^2/(2*g))= (200/1000)*10*(10^2/20) = 10.

13.

Work done in a system is ___(a) The measure of energy change(b) The measure of useful work(c) The measure of displacement(d) The measure of forceThe question was asked in class test.My enquiry is from Work topic in division Work, Energy and Power of Physics – Class 11

Answer»

The correct option is (a) The measure of energy change

For explanation I would say: WORK done in any system is a measure of the energy change in the system with its SURROUNDINGS. Work done and energy change are in PRACTICE the same. When a force is applied on a body and it MOVES and does some work. The amount of work done denotes energy change of the system with its surroundings.

14.

How many Ergs are there in 1 Joule?(a) 10(b) 10^4(c) 10^7(d) 10^9I have been asked this question in an online quiz.This intriguing question comes from Introduction to Work, Energy and Power in section Work, Energy and Power of Physics – Class 11

Answer» CORRECT CHOICE is (C) 10^7

For explanation I would say: Erg is the unit of energy in CGS SYSTEM. One Joule = 10^7 ergs. This can be found out by putting in the CGS units in the expression for energy.
15.

What is the correct expression for Work?(a) W = F * ds(b) W = P/t(c) W = E(d) W = E/tThe question was asked in an internship interview.I would like to ask this question from Introduction to Work, Energy and Power in portion Work, Energy and Power of Physics – Class 11

Answer» CORRECT answer is (a) W = F * ds

Easy explanation: WORK occurs when a force is applied on a BODY some displacement occurs as a result. Work is QUANTIFIED as force multiplied by displacement. Hence, W = F * s. Instantaneous work is given as W = F * ds.
16.

The work-energy theorem is valid only for positive work done.(a) True(b) FalseThis question was addressed to me in semester exam.My question is based upon Work-Energy Theorem for a Variable Force in section Work, Energy and Power of Physics – Class 11

Answer»

Correct OPTION is (b) False

The best explanation: Work energy THEOREM holds for both positive and NEGATIVE work DONE. If the work doneis positive then final kinetic energy increases by the amount of the work and if work done is negative then final kinetic energy decreases by the amount of work done.

17.

The potential energy of an object of constant mass and fixed reference is determined by its _____(a) mass(b) gravitational acceleration(c) position(d) velocityThis question was posed to me in class test.Origin of the question is Potential Energy topic in section Work, Energy and Power of Physics – Class 11

Answer»

The correct ANSWER is (c) position

Explanation: PE = m x g x h

The mass of the given object is CONSTANT.

The FIXED reference indicates constant acceleration due to gravity.

Hence, VARIATION in height (h) is nothing but a variation in position.

Hence, the potential energy of an object of constant mass and fixed reference is DETERMINED by its position.

18.

A car having a mass of 1 metric ton is moving with a speed of 30 m/s. It suddenly applies the brakes and skids to rest in a certain distance d. The frictional force between the tyres and road is 6000 N. What is the value of d?(a) 25 m(b) 50 m(c) 75 m(d) 100 mThis question was addressed to me in exam.Query is from Work-Energy Theorem for a Variable Force in chapter Work, Energy and Power of Physics – Class 11

Answer» RIGHT option is (c) 75 m

Easiest EXPLANATION: Let; m = 1000 kg

From Work-Energy theorem

Kf – Ki = F * d

0 – (1/2 * m * v^2) = -6000 * d

1/2 x 1000 x 30^2 = 6000 x d

d = 75 m.
19.

A force F = (5i – 3j +2k) N moves a particle from r1 = (2i + 7j + 4k) m to r2 = (5i + 2j + 8k) m. What is the work done by the force?(a) 18 J(b) 28 J(c) 38 J(d) 48 JThis question was addressed to me in an online interview.I want to ask this question from Work Done by a Variable Force topic in portion Work, Energy and Power of Physics – Class 11

Answer»

The correct answer is (c) 38 J

The best explanation: Displacement (d) = r2 – r1

 = (3I5J + 4K) m

Work = Force . Displacement; [Dot product of vectors]

 = (5i – 3j +2k) .(3i – 5j + 4k)

 = 38 J.

20.

An external force is acting on a system, the work done on the system is change in its kinetic energy.(a) True(b) FalseI got this question in an international level competition.My question is from Kinetic Energy topic in division Work, Energy and Power of Physics – Class 11

Answer» CORRECT choice is (a) True

To elaborate: The total work DONE on a BODY or SYSTEM is the change in its total kinetic energy when an external force is APPLIED on it.
21.

A body of mass 40 Kg covers a distance of 50 m in 5s starting from rest under the influence of a force. What is the work done by the force on the body?(a) 8000 J(b) -8000 J(c) 20000 J(d) 800 JThis question was posed to me in homework.This question is from Work in portion Work, Energy and Power of Physics – Class 11

Answer»

Correct answer is (a) 8000 J

The BEST explanation: Since the distance and time TAKEN are given, we can find out the acceleration of the BODY by the second equation of motion which is 4 m/s^2. From the second law of motion, the force can be found. Force = 160 N. From the force and the displacement, the work can be found out. Work = 8000 J.

22.

Energy is ________(a) Work(b) The ability to create work(c) Quantification of work(d) Force multiplied by displacementThe question was asked in final exam.My question is based upon Introduction to Work, Energy and Power topic in chapter Work, Energy and Power of Physics – Class 11

Answer»

The correct answer is (b) The ability to CREATE work

The explanation: Energy is defined as the ability to create work. When a force is applied on a BODY to create displacement, work TAKES place. Work is quantified by the force applied by the displacement. Whereas the energy is the ability of the force to create work. In general, the TOTAL INPUT energy = total output energy + work.

23.

When e < 1, the kinetic energy in the collision is ____(a) Lost(b) Gained(c) Gained exponentially(d) UnchangedThe question was posed to me in a national level competition.This question is from Collision in division Work, Energy and Power of Physics – Class 11

Answer»

The CORRECT option is (a) Lost

Easiest explanation: Coefficient of restitution or e can be UNDERSTOOD as the measure of how much KINETIC energy is REMAINING after the collision. As e becomes lesser and lesser, more kinetic energy is lost in the collision. This can be easily understood with by deriving the coefficient of restitution in a completely elastic collision.

24.

When two same masses travelling in opposite directions with different velocities collide perfectly elastically, their velocities ______(a) Exchange(b) Remain unchanged(c) Increase(d) DecreaseThe question was asked in examination.Question is from Collision in chapter Work, Energy and Power of Physics – Class 11

Answer»

Correct OPTION is (a) Exchange

The explanation: In this CASE also we need to conserve the MOMENTUM and WRITE the expression for e. After doing so we will find that the sum of the initial velocities is equal to the sum of the final velocities. Same goes for the difference (with slight alterations). This will result in the final velocity of one body being equal to the initial velocity of the other. Hence, the velocities will get exchanged.

25.

A spring of length 1m has two cars connected to both of its ends. The two cars move towards eachother such that the spring is compressed to 0.5m. If the spring constant is 500 N/m, what is the elastic potential energy stored?(a) 125 J(b) -125 J(c) 62.5 J(d) -62.5 JThe question was asked by my school teacher while I was bunking the class.The question is from The Potential Energy of a Spring in division Work, Energy and Power of Physics – Class 11

Answer» CORRECT choice is (C) 62.5 J

The BEST explanation: PE = 1/2*k*d^2

 = 1/2 x 500 x (-0.5) ^2

 = 62.5 J.

The elastic potential energy is POSITIVE even for negative displacement.
26.

When a roller coaster is at the top of a steep hill, its potential energy is maximum. When it hurdles down the slope and comes to the bottom, the potential energy reduces greatly. Hence we can say that the law of conservation of energy is not valid here since energy is destroyed.(a) True(b) FalseThe question was posed to me by my school principal while I was bunking the class.My question is taken from Various Forms of Energy : The Law of Conservation of Energy in chapter Work, Energy and Power of Physics – Class 11

Answer»

Right answer is (b) False

The explanation: When a roller coaster is at the top of a steep hill, its POTENTIAL ENERGY is MAXIMUM. When it hurdles down the slope and comes to the bottom, the potential energy reduces greatly. However, kinetic energy increases. Thus, there is a CHANGE from potential energy to kinetic energy and hence no destruction of energy.

27.

For what value of e is a collision partially elastic?(a) 0 < e < 1(b) 1(c) e > 1(d) 0This question was addressed to me during an internship interview.This is a very interesting question from Collision topic in chapter Work, Energy and Power of Physics – Class 11

Answer»

The CORRECT choice is (a) 0 < e < 1

The best I can explain: Partially ELASTIC collision occurs when the value of e is LESS than one and more than zero. In this CASE the collision is neither perfectly elastic nor perfectly INELASTIC. Hence, we call it partially elastic collision.

28.

The maximum value of static friction when the body is at the verge of starting motion is known as _____(a) Static friction(b) Limiting friction(c) Impending motion(d) Angle of reposeI have been asked this question by my college professor while I was bunking the class.This interesting question is from Friction in chapter Work, Energy and Power of Physics – Class 11

Answer»

Correct answer is (b) Limiting friction

To elaborate: The value of limiting friction can be found by equating it to the PRODUCT of the STATIC frictional COEFFICIENT and normal REACTION force of the body.

29.

Which of the following is not a variable force?(a) F = x(b) F = y^2(c) F = 2(d) F = 2*tI got this question in exam.My question is from Work Done by a Variable Force topic in chapter Work, Energy and Power of Physics – Class 11

Answer»

Right choice is (C) F = 2

Easiest explanation: F = x, F = x^2 varies with x and y co-ordinate RESPECTIVELY. F = 2*t varies with time but F = 2 is ALWAYS CONSTANT.

30.

A bucket filled with water weighing 20 kg is raised from a well of depth 20 m. If the linear density of the rope is 0.2 kg/m, the work done is _____ (Assume g = 10m/s^2)(a) 4000 J(b) 4040 J(c) 4400 J(d) 4800 JI got this question in an internship interview.This intriguing question originated from Work Done by a Variable Force topic in division Work, Energy and Power of Physics – Class 11

Answer» CORRECT choice is (c) 4400 J

To elaborate: Mass DENSITY (p) = 0.2 kg/m

Length (l) = 20 m

Force = F(x)

 = m(x)*g

 = 0.2x*g

 = 2x

Displacement (d) = 20 m

Work = \(\int_{0}^{l}\)f(x)dx+ (20*g*20)

 = \(\int_{0}^{20}\)2xdx + 4000

 = 4400 J.
31.

If mass (m) is doubled and velocity (v) is halved then _____(a) Kinetic energy decreases by half(b) Potential decreases by half(c) Momentum decreases by half(d) Potential and kinetic energy remains unchangedThe question was posed to me in an interview.My doubt stems from Kinetic Energy in chapter Work, Energy and Power of Physics – Class 11

Answer»

Right choice is (a) Kinetic energy decreases by half

To explain I WOULD SAY: Momentum doesn’t CHANGE i.e. (2m)*(v/2). K.E decreases by half while P.E BECOMES TWICE the original value.

32.

For an object of 1kg mass to escape the gravitational force of the earth, the kinetic energy imparted to it from the surface of the earth is approximately _____(a) 5600 J(b) 10200 J(c) 11200 J(d) 12000 JI got this question in final exam.My question is taken from Kinetic Energy topic in section Work, Energy and Power of Physics – Class 11

Answer»

Right option is (a) 5600 J

To EXPLAIN I WOULD say: Escape velocity of EARTH from the surface (v) = 11.2 km/s

 = 11,200 m/s

KE = (1/2) X m x v^2

 = (1/2) x 1 x 11,200

 = 5600 J.

33.

A force of 40 N acts on body of mass 5 Kg which is initially at rest. What is the amount of work done in the first 10 s?(a) 16000 J(b) -16000 J(c) 400 J(d) -400 JThis question was addressed to me in an interview for internship.The above asked question is from Work in chapter Work, Energy and Power of Physics – Class 11

Answer»

The CORRECT answer is (a) 16000 J

To explain: The work done on a body is obtained by CALCULATING the DOT product of the force and displacement vector. From Newton’s second law, we get the acceleration EQUAL to 8 m/s^2. From the second equation of motion the displacement COVERED can be obtained which is equal to 400 m. On taking the dot product of the force and displacement, we get work done equaling to 16000 J.

34.

The maximum potential energy in a roller coaster is at _____(a) the top of the steep climb(b) somewhere during the climb(c) somewhere during the descent(d) the lowest point after the climbI had been asked this question during an interview.This intriguing question comes from Various Forms of Energy : The Law of Conservation of Energy topic in chapter Work, Energy and Power of Physics – Class 11

Answer»

Correct option is (a) the top of the STEEP climb

The BEST I can explain: The potential ENERGY is given by;

PE = m x g x h

where;

PE = Potential energy

m = Mass of the object

g = ACCELERATION due to gravity

h = Height of the object

Hence, the higher the object, the greater the potential energy.

35.

The dimensions of energy are _____(a) [ML^2T^-2](b) [MLT^-2](c) [ML^2T^-1](d) [MLT^-1]This question was posed to me in semester exam.The doubt is from Various Forms of Energy : The Law of Conservation of Energy in division Work, Energy and Power of Physics – Class 11

Answer»

The correct choice is (a) [ML^2T^-2]

To ELABORATE: Energy = FORCE x Displacement

Units of energy = KG x (m/s^2) x m

 = kg x m^2 x s^-2

Therefore;

Dimensions of energy = [ML^2T^-2].

36.

The elastic potential energy varies linearly with displacement.(a) True(b) FalseThis question was addressed to me in homework.This question is from The Potential Energy of a Spring topic in division Work, Energy and Power of Physics – Class 11

Answer»

Right ANSWER is (b) False

Easy EXPLANATION: PE = 1/2 x k x d^2; where d = Displacement

Equation of PARABOLA: y = 4x^2

By comparing the two EQUATIONS, we can conclude that the elastic potential energy varies parabolically with displacement and not linearly.

37.

What are the types of kinetic friction?(a) Sliding friction, rolling friction and adhesive friction(b) Sliding friction and rolling friction(c) Rolling friction and adhesive friction(d) Sliding friction and adhesive frictionThe question was asked during an interview.Enquiry is from Friction topic in section Work, Energy and Power of Physics – Class 11

Answer»

The correct choice is (B) SLIDING friction and rolling friction

For explanation I would say: Kinetic friction is of two types; sliding and rolling. Rolling friction is less than sliding friction. This is the REASON why rolling a BODY is always easier than sliding a body.

38.

What work must be done to stop a bullet moving with a velocity of 2000ms^-1 and having a mass of 50g?(a) 10^5J(b) 10^6J(c) 10^4J(d) 10^7JThe question was asked by my college director while I was bunking the class.I'd like to ask this question from Kinetic Energy in division Work, Energy and Power of Physics – Class 11

Answer» RIGHT OPTION is (a) 10^5J

The BEST I can explain: Work done against a BODY is the energy LOST (kinetic) by it. Energy formula is 0.5*m*v^2. So, 0.5*(50/1000)*2000^2 = 10^5.
39.

A force of 600 N elongates a spring from its natural length of 18 cm to a length of 20 cm. What is the work done?(a) 116J(b) 114J(c) 118J(d) 120JI have been asked this question during an interview for a job.This key question is from Work Done by a Variable Force topic in division Work, Energy and Power of Physics – Class 11

Answer»

The correct choice is (b) 114J

The BEST explanation: The force on a spring stretched by x meters is given by F = K*x where k is the spring constant. So, 600 = k*(2/100). Now k = 3*10^4, and hence F = 30000*x. W = \(\int_{x1}^{x2}\)F * dx = \(\int_{0.18}^{0.2}\)30000 * x * dx = 114 J.

40.

A body is falling freely from rest from a height of 100m. The ratio of kinetic energy after 2 and 5 seconds is _____(a) 2:5(b) 4:25(c) 25:4(d) 5:2This question was posed to me in quiz.This question is from Kinetic Energy topic in section Work, Energy and Power of Physics – Class 11

Answer»

The CORRECT option is (b) 4:25

Easiest EXPLANATION: From newtons law;

v1 = u + gt1

v1 = 2g

v2 = u + gt2

v2 = 5g

KE1 : KE2 = v1^2 : v2^2

 = 4 : 25.

41.

The kinetic energy of a man is half that of a boy whose mass is half that of the man. When the man speeds up by 5 m/s, his kinetic energy doubles that of the boy’s kinetic energy. What is the initial velocity of the man?(a) 5 m/s(b) 10 m/s(c) 15 m/s(d) 20 m/sI have been asked this question in quiz.This question is from Kinetic Energy in division Work, Energy and Power of Physics – Class 11

Answer»

Right answer is (a) 5 m/s

The explanation: The kinetic energy of MAN (initial) = KE

 = KE’/2

The kinetic energy of man (FINAL) = 2 x KE’

The kinetic energy of boy = KE’

Mass of man = M

Mass of boy = m

 = M/2

v = Initial VELOCITY of man

v’ = Initial velocity of boy

(1/2) x M x v^2= (1/2) x m x v’^2

 = (1/2) x M/2 x v’^2

Therefore; v = v’/2^0.5

(1/2) x M x (v+5) ^2=2 x (1/2) x m x v’^2

 = 2 x (1/2) x M/2 x (2 x v^2)

(v+5) ^2 = 4 x v^2

v + 5 = 2 x v

v = 5m/s.

42.

The work done on a body of mass 5 Kg is 70 J. What is the magnitude of the force applied if the total displacement it covered is 7 m.(a) 10 N(b) -10 N(c) 20 N(d) 70 NI got this question at a job interview.My question is taken from Work in section Work, Energy and Power of Physics – Class 11

Answer»

Right choice is (a) 10 N

Explanation: The amount of WORK done on a body is obtained by calculating the dot product of the FORCE and the displacement. Due to lack of information, we ASSUME that the force and the displacement are in the same direction. Since the total work done is given, we can find out the applied force by DIVIDING the total work done by the total displacement. By doing so we get force applied = 10 N.

43.

A body moving with a constant velocity on normal ground initially has an energy of 1000 J. If the final energy is 800 J, what is the work done and which force causes this work?(a) 200 J, gravity(b) -200 J, friction(c) 200 J, friction(d) -200 J, gravityThe question was posed to me in an interview.My question is taken from Work-Energy Theorem topic in portion Work, Energy and Power of Physics – Class 11

Answer» CORRECT option is (B) -200 J, friction

To explain I would say: According to the work-ENERGY theorem, the total change in energy is equal to the total work done. The change in energy is -200 J. Hence the work done is -200 J. Since it is mentioned that the body is moving on a normal ground, there is force is friction. THEREFORE, friction is what causes this work.
44.

A body of mass 2 Kg, initially at rest, moves under the influence of an external force of magnitude 4 N on plane ground. What is the work done by the force and the change in kinetic energy in the first 10 seconds?(a) 400 J, 400 J(b) -400 J, 400 J(c) 400 J, -400 J(d) -400 J, -400 JThe question was asked in a national level competition.This key question is from Work-Energy Theorem in chapter Work, Energy and Power of Physics – Class 11

Answer»

The CORRECT choice is (a) 400 J, 400 J

To explain I would say: By work-ENERGY theorem, the TOTAL work done on a BODY is equal to the change in the total energy. K.E. = \(\Big(\frac{1}{2}\Big)\)mv^2. The acceleration of the body is 4/2 = 2 m/s^2. The final velocity after 10 s can be found out by the first equation of motion. The total change in the total energy is the total change in kinetic energy as the body is moving on plane ground and is equal to 400 J. Hence the work done is 400 J.

45.

A car of mass 1ton is moving with a velocity of 25 m/s towards left. A truck of mass 5 ton is moving towards left with a velocity of 3 m/s. If the collision is perfectly elastic, what is the final velocity of the truck in m/s?(a) 11(b) 25(c) 3(d) 10This question was posed to me in my homework.This question is from Collision topic in section Work, Energy and Power of Physics – Class 11

Answer»

Right choice is (c) 3

To EXPLAIN: The initial momentum of the system = momentum of car + momentum of truck = 40 Kg-m/s leftwards. Since the momentum is conserved, the initial momentum = FINAL momentum. Hence the final momentum is 40 Kg-m/s leftwards. The collision is perfectly elastic, THEREFORE, e = 1. Therefore, final relative velocity (of truck with respect to car) = initial relative velocity (of truck with respect to car). Sum of the final velocities of the car and the truck = 4 m/s. From this information and the conservation of momentum, one can FIND the final velocity of the truck.

46.

What is the coefficient of restitution (e)?(a) Ratio of final to initial relative velocities(b) Ratio of initial to final relative velocities(c) Ratio of final to initial velocity of a body(d) Product of initial to final relative velocitiesI had been asked this question in examination.Query is from Collision topic in section Work, Energy and Power of Physics – Class 11

Answer» RIGHT CHOICE is (a) RATIO of final to initial relative velocities

To explain I would say: The coefficient of RESTITUTION (e) is the ratio of the final to initial relative velocities in a collision system. If the value of e = 1, then the collision is PERFECTLY elastic. If it is equal to 0, then the collision is perfectly inelastic.
47.

Consider 2 balls A and B of the same mass. The potential energy of ball A is thrice that of ball B. How high is ball A compared to ball B?(a) Same height as ball B(b) Twice as high height as ball B(c) Thrice as high height as ball B(d) Four times as high height as ball BThis question was posed to me in a national level competition.My doubt stems from Potential Energy topic in division Work, Energy and Power of Physics – Class 11

Answer»

The correct choice is (c) Thrice as HIGH height as ball B

Explanation: PEa = (m x g x h) a

PEb = (m x g x h) b

ma = MB = m

GA = gb = g

PEa = 3 x PEb

ma x ga x ha = mb x gb x hb x 3

m x g x ha = m x g x hb x 3

ha = 3 x hb.

48.

A rope has a uniform mass density of 0.4 kg/m. The rope is 10 m long and is lowered into a 10 m deep pit. The bottom part of the rope just touches the bottom of the pit. What is the work done to pull the rope out of the well completely? (Assume g = 10m/s^2)(a) 200 J(b) 400 J(c) 2000 J(d) 4000 JI had been asked this question during an internship interview.I want to ask this question from Work Done by a Variable Force in section Work, Energy and Power of Physics – Class 11

Answer»

Correct OPTION is (a) 200 J

Easiest explanation: MASS DENSITY (p) = 0.4 kg/m

Length (l) = 10 m

Force = f(X)

 = m(x)*G

 = 0.4x*g

 = 4x

Displacement (d) = 10 m

Work = \(\int_{0}^{l}\)f(x)dx

 = \(\int_{0}^{10}\)4xdx

 = 200 J.

49.

A force of 10 N creates a displacement of 2 m but the work done on the body throughout its motion is equal to 70 J. What possibly can be the reason or this?(a) There are multiple forces action on the body(b) The body is at rest(c) The force is not uniform(d) The displacement is harmonicThis question was addressed to me during a job interview.Question is from Work topic in chapter Work, Energy and Power of Physics – Class 11

Answer»

Correct answer is (a) There are multiple forces ACTION on the body

To explain I would say: The possible reason for this is that multiple forces are acting on the body at different instances throughout its MOTION. The work DONE on a body is a MEASURE of the energy exchanged between the body and the environment and is usually the total work done. Work done due to the given force is 20 J but this need not be the total work done.

50.

The total energy change of a body which covers a vertical height is constituted completely by the potential energy change only when ______(a) It moves slowly(b) It moves quickly(c) It moves for some time, then rests, then moves again(d) It moves with a decreasing velocityThe question was asked by my college director while I was bunking the class.The above asked question is from Work-Energy Theorem topic in section Work, Energy and Power of Physics – Class 11

Answer»

Correct answer is (a) It MOVES slowly

For explanation: The total change in energy is CONSTITUTED by the changes in POTENTIAL and kinetic energies. When the body is moving slowly, it implies that the body is moving with such a small velocity that the square of the velocity in the expression of kinetic energy becomes negligible. Hence, the total change in the energy is constituted by the total change in the potential energy.