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101.

Find the ratio of potential energy if an object is raised to thrice of its height and its mass is tripled.(a) 1:1(b) 1:4(c) 1:9(d) 1:3The question was posed to me in unit test.This interesting question is from Potential Energy topic in division Work, Energy and Power of Physics – Class 11

Answer»

Correct answer is (c) 1:9

To ELABORATE: PE1 = m x G x h

PE2 = (3M) x g x (3H)

 = 9 x m x g x h

PE1 : PE2 = mgh : 9mgh

 = 1:9.

102.

The change in the total energy of a body moving because of work being done on it is attributed by the change in kinetic energy only when ______(a) It moves extremely slowly(b) It moves with a very high velocity(c) It moves on an equipotential surface(d) It moves with a positive accelerationI had been asked this question in an interview for job.This interesting question is from Work-Energy Theorem topic in division Work, Energy and Power of Physics – Class 11

Answer»

Correct option is (c) It moves on an equipotential surface

Easiest EXPLANATION: An equipotential surface is defined as a surface on which the POTENTIAL of the body is same everywhere. Hence the potential of a body moving on an equipotential surface does not CHANGE. THEREFORE, the total change in energy is ATTRIBUTED by the change in the kinetic energy of the body.

103.

According to the work-energy theorem, total change in energy is equal to the _______(a) Total work done(b) Half of the total work done(c) Total work done added with frictional losses(d) Square of the total work doneThe question was posed to me in final exam.My doubt stems from Work-Energy Theorem topic in portion Work, Energy and Power of Physics – Class 11

Answer»

Right choice is (a) Total WORK DONE

Best explanation: ACCORDING to the work-energy theorem, the total change in the energy of the system is equal to the total work done. LOSSES due to friction are also a part of the total work. The total work done is the sum of the work done by all the forces.

104.

The energy possessed by a body by the virtue of its position is called ______(a) Kinetic energy(b) Potential energy(c) Total energy(d) Position energyThe question was posed to me in class test.I'd like to ask this question from Introduction to Work, Energy and Power in division Work, Energy and Power of Physics – Class 11

Answer»

The correct answer is (b) POTENTIAL ENERGY

The best explanation: The potential energy of a body EMERGES due to its position. More specifically, the displacement of a body from the reference position decides the amount of potential energy it has. Usually, the potential energy of a body with mass m is given as P.E.=mgh, where h is the height of the body from the GROUND plane and g is the acceleration due to gravity. ABSOLUTE potential of a body cannot be found. Only the relative value can be found out.

105.

_____ is known as the motion that would take place under the applied force if friction were absent.(a) Impending motion(b) Constrained motion(c) Unconstrained motion(d) Linear motionThis question was addressed to me by my college professor while I was bunking the class.Question is from Friction topic in section Work, Energy and Power of Physics – Class 11

Answer»

Right option is (a) Impending MOTION

The best explanation: Impending motion is known as the motion that WOULD take place under the applied force if friction were absent. The motion which can’t proceed arbitrarily in any manner is called constrained motion. Motion without any restriction is known as an UNCONSTRAINED motion. ONE dimensional motion ALONG a straight line is known as linear motion.

106.

What is the SI unit of variable force?(a) Newtons(b) Joules(c) Ampere(d) MoleThe question was posed to me during an online exam.Enquiry is from Work Done by a Variable Force topic in portion Work, Energy and Power of Physics – Class 11

Answer»

The correct CHOICE is (a) NEWTONS

Easy explanation: The SI unit of FORCE is Newtons. While Joules, Ampere, and Mole are SI units of ENERGY, current and amount of SUBSTANCE.

107.

A body is projected up vertically with a velocity of 60 m/s. What percentage of its initial kinetic energy is converted into potential energy after 3 seconds? (Take g = 10 m/s^2)(a) 25 %(b) 50%(c) 75%(d) 100%I had been asked this question by my school teacher while I was bunking the class.My query is from Kinetic Energy in section Work, Energy and Power of Physics – Class 11

Answer»

Correct answer is (c) 75%

Best explanation: Initial KE = (1/2) x M x (60 x 60)

 = 1800 x M

From Newton’s laws;

s = UT + (1/2)gt^2

 = (60 x 3) – (10 x 3 x 3)/2

 = 180 – 45

 = 135 m

POTENTIAL ENERGY at 135m (PE) = M x g x s

 = 1350 x M

So KE at 135m = Initial KE – PE

 = 1800M – 1350M

 = 450M J; This is 25% of the initial kinetic energy. Hence, 75% is converted into potential energy.

108.

Work done by a force on a body is an example of ______(a) Mechanical work(b) Electrical work(c) Magnetic work(d) Thermodynamic workThe question was posed to me in semester exam.My question is from Work topic in chapter Work, Energy and Power of Physics – Class 11

Answer»

The correct OPTION is (a) Mechanical WORK

Explanation: The work DONE by a force on a body is CALLED as mechanical work. In mechanical work, the mechanical energy of the body changes. Mechanical work = W = \(\vec{F}.\vec{s}\), where F is the force and s is the displacement.

109.

Power is ______(a) Rate of doing work(b) Ability to do work(c) Rate of energy creation(d) Equivalent to workThis question was posed to me in an internship interview.I'd like to ask this question from Introduction to Work, Energy and Power in section Work, Energy and Power of Physics – Class 11

Answer»

Correct CHOICE is (a) Rate of doing WORK

To explain: Power is DEFINED as the rate of doing work. The ability to do work is energy. Energy can NEITHER be created nor be destroyed, hence, the rate of energy creation does not exist.

110.

A 200 kg wagon climbs up a hill of slope 30-degrees in 1 minute at a speed of 10 m/s. How much power is delivered by the engine? (Assume g = 10m/s^2)(a) 10 kW(b) 20 kW(c) 30 kW(d) 40 kWI had been asked this question during an interview.My doubt stems from Power topic in chapter Work, Energy and Power of Physics – Class 11

Answer»

The correct answer is (B) 20 KW

Easy explanation: WEIGHT of car = m x g

 = 2,00 x 10

 = 2,000 N

Total force (F) = 2,000

Velocity (v) = 10 m/s

P = F x v

 = 2000 x 10

 = 20,000 W

 = 20 kW.

111.

A 200 kg wagon climbs up a hill of slope 30-degrees in 1 minute at a speed of 36 km/h. How much power is delivered by the engine if the frictional force is 25% of the weight of the car? (Assume g = 10m/s^2)(a) 25 kW(b) 50 kW(c) 100 kW(d) 125 kWI got this question in an international level competition.Asked question is from Power in portion Work, Energy and Power of Physics – Class 11

Answer»

The correct ANSWER is (a) 25 kW

Easiest explanation: Weight of car = m x g

 = 200 x 10

 = 2,000 N

Frictional force = (25/100) x (2,000)

 = 500 N

Total force (F) = 2000 + 500

 = 2,500 N

Velocity (v) = 36 km/h

 = 36 x (1000/3600)

 = 10 m/s

P = F x v

 = 2500 x 10

 = 25 kW.

112.

How much should a spring of indefinite length be compressed to have a potential energy equivalent to a ball of mass 6 kg raised to a height of 120 m above the ground? Let the spring have a stiffness of k = 100 N/m and assume g = 10 m/s^2.(a) 6m(b) 12m(c) 20m(d) 144mI have been asked this question in semester exam.I want to ask this question from The Potential Energy of a Spring topic in chapter Work, Energy and Power of Physics – Class 11

Answer»

Correct OPTION is (b) 12m

To elaborate: PE of ball = m x g x h

 = 6 x 10 x 120

 = 7200 J

PE of spring = 1/2 x k x d^2

Given;

PE of ball = PE of spring

7200 = 1/2x k x d^2

 = 1/2 x 100 x d^2

d^2 = 144

d = 12 m.

113.

A body of mass 3 kg starts from rest with a uniform acceleration of unknown magnitude. If the body has a velocity of 30 m/s in 6 seconds, what is the power consumed in 3 seconds?(a) 125 W(b) 225 W(c) 325 W(d) 425 WI had been asked this question in unit test.Query is from Power topic in section Work, Energy and Power of Physics – Class 11

Answer»

Right option is (b) 225 W

Easy EXPLANATION: V = u + at

30 = a x 6

a = 5 m/s^2

Force (F) = m x a

 = 3 x 5

 = 15 N

v’ = u + at’

v’ = 5 x 3

 = 15 m/s

Power consumed in 3 seconds = F x v’

 = 15 X 15

 = 225 W.

114.

If a box is lying on the floor of a wagon with a coefficient of friction 0.2, what is the maximum acceleration of the wagon for which the box would remain stationary? (Let g = 9.81 m/s^2)(a) 1.96 m/s^2(b) 2 m/s^2(c) 3.92 m/s^2(d) 4 m/s^2I have been asked this question by my school principal while I was bunking the class.My question comes from Friction in portion Work, Energy and Power of Physics – Class 11

Answer»

The correct OPTION is (a) 1.96 m/s^2

Easiest EXPLANATION: Let the mass of the box be “m”

ma = u x mg

a = u x g

a = 0.2 x 9.81

 = 1.96 m/s^2.

115.

The kinetic energy of a body is ‘K’. If one-fourth of its mass is removed and velocity is doubled, the new kinetic energy will be _____(a) K(b) 3K(c) 4K(d) 9K/4I have been asked this question in a national level competition.This question is from Kinetic Energy topic in division Work, Energy and Power of Physics – Class 11

Answer»

Right OPTION is (b) 3K

The best explanation: K = 1/2 x m x V^2

New kinetic ENERGY (K’) = 1/2 x m’ x v’^2

m’ = 3m/4; [one-fourth of mass is REMOVED]

v’ = 2v; [velocity is DOUBLED]

K’ = 1/2 x (3m/4) x (2v) ^2

 = 1/2 x m x v x 3

 = 3 x K

 = 3K.

116.

Limiting friction of a body depends on _____(a) Area of contact of surfaces(b) The volume of the smaller body on larger surface(c) Nature of surfaces(d) The periphery of the contact surfacesThe question was posed to me during an internship interview.The query is from Friction topic in section Work, Energy and Power of Physics – Class 11

Answer»

The CORRECT answer is (c) Nature of surfaces

For explanation I WOULD SAY: Since limiting friction depends only of the coefficient of friction of the surfaces, it, therefore, depends only of the nature of the SURFACE, i.e., smoothness or roughness.

117.

The force required to tow a vehicle at constant velocity is directly proportional to the magnitude of velocity raised to the first power. It requires 1000 W to tow with a velocity of 10 m/s. How much power is required to tow at a velocity of 8 m/s?(a) 320 W(b) 640 W(c) 160 W(d) 80 WThis question was posed to me during a job interview.I would like to ask this question from Power in chapter Work, Energy and Power of Physics – Class 11

Answer»

Correct option is (B) 640 W

To elaborate: Since force is directly proportional to VELOCITY, the power REQUIRED will be directly proportional to the square of the velocity.

Power = Force x Velocity

Hence, power is a multiple of 8^2 and an INTEGER such that;

1000/10^2 = P/8^2

P = 640 W.

118.

An object is thrown from the ground with a velocity of 5 m/s.If the object has a mass of 2kg, what will be its potential energy at the top-most point of its trajectory? (Assume g = 10 m/s^2)(a) 5 J(b) 15 J(c) 25 J(d) 50 JI have been asked this question in an international level competition.Question is from Potential Energy topic in portion Work, Energy and Power of Physics – Class 11

Answer»

Right answer is (c) 25 J

For EXPLANATION I WOULD say: Maximum HEIGHT reached by the object;

h = v^2/(2 x G)

 = 25/20

 = 1.25 m

PE = m x g x h

 = 2 x 10 x 1.25

 = 25 J.

119.

The potential energy of an object cannot be increased by internal forces.(a) True(b) FalseI had been asked this question in an online interview.This is a very interesting question from Potential Energy topic in division Work, Energy and Power of Physics – Class 11

Answer»

Right OPTION is (a) True

To elaborate: The POTENTIAL ENERGY can only be increased by external forces. Energy increase by internal forces manifests as an increase in kinetic energy. However, potential energy can be REDUCED by internal forces by increasing kinetic energy.

120.

A 10kg object is raised to a height of 20m. What is the magnitude of its potential energy? (Assume g = 10 m/s^2)(a) 500 J(b) 1000 J(c) 1500 J(d) 2000 JI had been asked this question during an online interview.My query is from Potential Energy in portion Work, Energy and Power of Physics – Class 11

Answer»

The correct ANSWER is (d) 2000 J

To EXPLAIN I would say: PE = m x G x h

m = 10 kg

g = 10 m/s^2

h = 20 m

PE = 10 x 10 x 20

 = 2000 J.

121.

The total energy of a system moving under the action of a conservative force changes by 50 J. Which of the following statements are correct with regards to the amount of work done?(a) Amount of work done = 50 J(b) Amount of work done < 50 J(c) Amount of work done > 50 J(d) Amount of work done

Answer»

Right answer is (a) Amount of WORK done = 50 J

For explanation: By work-energy theorem, the total work done on a body is equal to the change in the total energy. No matter what kind of FORCE is ACTING on the SYSTEM, the theorem upholds. Since the total change in the energy is of 50 J, the total work done is equal to 50 J.

122.

A person of mass 50 kg carrying a load of 20 kg walks up a staircase. The width and height of each step are 0.25 m and 0.2 m respectively. What is the work done by the man in walking 20 steps?(Assume g = 10m/s^2)(a) 800 J(b) 1600 J(c) 2000 J(d) 2800 JI got this question in class test.I would like to ask this question from Work Done by a Variable Force topic in chapter Work, Energy and Power of Physics – Class 11

Answer» CORRECT choice is (d) 2800 J

Best explanation: Total MASS (m) = 50 + 20 = 70 kg

Vertical displacement = 0.2 x 20 = 4m

Horizontal displacement = 0.25 x 20 = 5m

Displacement = (5I + 4j) m

Force = m x acceleration

 = 70 x (0i + 10j)

 = (700j) N

Work = Force .Displacement

 = (0i + 700j) . (5i + 4j)

 = 2800 J.