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An object is thrown from the ground with a velocity of 5 m/s.If the object has a mass of 2kg, what will be its potential energy at the top-most point of its trajectory? (Assume g = 10 m/s^2)(a) 5 J(b) 15 J(c) 25 J(d) 50 JI have been asked this question in an international level competition.Question is from Potential Energy topic in portion Work, Energy and Power of Physics – Class 11

Answer»

Right answer is (c) 25 J

For EXPLANATION I WOULD say: Maximum HEIGHT reached by the object;

h = v^2/(2 x G)

 = 25/20

 = 1.25 m

PE = m x g x h

 = 2 x 10 x 1.25

 = 25 J.



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