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0.02 neighbourhood of 2: |
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Answer» Here. a = 2; δ = 0.02 In Modulus form: |x – a| < δ ∴ N(2. 0.02) = | x – 2| < 0.02 In Interval form: (a – 8, a + δ) ∴ N (2, 0.02) = (2 – 0.02, 2 + 0.02) = (1.98, 2.02) |
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