1.

0.02 neighbourhood of 2:

Answer»

Here. a = 2; δ = 0.02

In Modulus form: |x – a| < δ

∴ N(2. 0.02) = | x – 2| < 0.02

In Interval form: (a – 8, a + δ)

∴ N (2, 0.02) = (2 – 0.02, 2 + 0.02)

= (1.98, 2.02)



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