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0.2F capacitor is charged to 600V by a batteryOn removing the battery. It is connected withanether paralledl plate condenser (1.OP). Thepotential decreases to(B) 120 volts(D) 600 volts00 volts(C) 300 volts |
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Answer» total Charge stored = CV = 0.2*600 = 120C now, P.D across 1.F = Q/C = 120/1 = 120 V option B |
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