0.5 moles of CO thken in a 2 L flask is maintained at 750 k in the presence of a catalyst so that the following reaction can take place: CO+2H_(2) hArr CH_(3)OH. When hydrogen is introduced, the pressure of the system in increased to 23.629 antm from 15.129 atm at equilibrium and 0.08 moles of gaseous product, methanol is formed. Clculate k_(C).

0.5 moles of CO thken in a 2 L flask is maintained at 750 k in the pre

1.	0.5 moles of CO thken in a 2 L flask is maintained at 750 k in the presence of a catalyst so that the following reaction can take place: CO+2H_(2) hArr CH_(3)OH. When hydrogen is introduced, the pressure of the system in increased to 23.629 antm from 15.129 atm at equilibrium and 0.08 moles of gaseous product, methanol is formed. Clculate k_(C).
Answer» Solution :`CO+2H_(2) hArr CH_(3)OH` Initial moles `0.5 a0` At EQUILBRIUM 0.5=x a-2x x Given that x=0.08 Moles of CO=0.5-0.08=0.42 Moles of `H_(2)` =a-0.16 Moles of `CH_(3)OH=0.08` No. of moles of `H_(2)` can be calculated by using PV =nRT Pressure of hydrogen =23.629-15.129=8.5 ATM `n=(PV)/(RT)=(8.5xx2)/(0.082xx750)=0.276(a)` `therefore ` Number of moles of `H_(2)` at equilibrium =0.276-0.16=0.116 `K_(c)=(0.08//2)/(((0.166)/(2))^(2)xx(0.42)/(2))=56.66 l^(2) "mol"^(-1)`