1.

`0.6%` यूरिया विलयन का `25^(@)C` पर वाष्पदाब क्या होगा, यदि इस तापक्रम पर जल (घोलक) का वाष्पदाप 24 mm Hg है?

Answer» `(P_(A)^(0)-P_(A))/(P_(A)^(0))=(W_(B)M_(A))/(M_(B)W_(A))P^(0)=24.0mm Hg, `
`P = ? w =0.6, m =60, W=100g, M=18`
`implies(24-P_(A))/(24)=(0.6xx18)/(60xx100)`
`implies(24-P_(A))/(24)=(6xx18)/(600xx100)`
`implies(24-P_(A))=(18xx24)/(100xx100)`
`implies(24)/(1)-(18xx24)/(100xx100)=P_(A)`
`implies 24-0.0.432=P_(A)`
`P_(A)=23.957` mHg.


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