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`0 g` ice at `0^@C` is converted into steam at `100^@C`. Find total heat required . `(L_f = 80 cal//g, S_w = 1cal//g-^@C, l_v = 540 cal//g)` |
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Answer» Correct Answer - A::B::C `Q = mL_f+ms_w Deltatheta + mL_f` `= m(L_f + s_wDeltatheta + L_f)` `= 10[80 + 1 xx 100 + 540]` `=7200 cal` |
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