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A wall has two layers A and B, each made of different material. Both the layers have the same thickness. The thermal conductivity of the material of A is twice that of B . Under thermal equilibrium, the temperature difference across the wall is `36^@C.` The temperature difference across the layer A isA. `6^@C`B. `12^@C`C. `18^@C`D. `24^@C` |
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Answer» Correct Answer - C Thermal resistance, `R = l/(KA) prop 1/K rArr K_A = 2K_B` `:. R_A = (R_B)/2` So, let `R_A = R "then" R_B = 2R` Now, `H_A = H_B` `:. (TD)_A/R_A = (TD)_B/R_B or (TD)_A = (R_A/R_B)(TD)_B` `= (R/(2R))(36^@C) = 18^@C` . |
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