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Show that the SI units of thermal conductivity are `W//m-K`. |
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Answer» Correct Answer - A `Q= ((KA(theta_1-theta_2)t)/l)` `:. K = (Ql)/(A(theta_1-theta_2)t) = (J -m)/(m^2K-s)` `=W/(m-K) (as J//s=W)` . |
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