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0 TIiIl, 2.0 Inim.7. A beam of monochromatic light of wavelength500 nm falls on two parallel slits. The distancebetween the slits is 0.15 mm. Determine the width ofthe interference fringes on a screen placed at a distanceof 1.5 m from the slits.Ans. 5 mm. |
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Answer» fringe width is wavelength x distance of screen/slit differencehence=500*10^-9*1.5/0.15*10^-3=5mm |
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