1.

05 facar at restaccelerates unifomly to a speed of144 kmihin 20 second t covers a distance of-1)20m31440m2 400m(4) 2980 nm

Answer»

V = 144*5/18 = 40m/sv = u+at => a = V-0/20 = 40/20 = 2 m/s²

using Newton's 2nd formula of motion

S = 1/2*(a)*(t)²S = 1/2*(2)*(20)² = 400m

option 2



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