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07.A car moving with a speed of 40 km/h can bestopped after 2 m by applying brakes. If thesame car is moving with a speed of 80 km/hwhat is the minimum stopping distance?(1) 8 m3) 4 m(2) 6 m(4) 2 mna

Answer»

If F is retarding force and s the stopping distance then 1/2 m2 =Fs For same retarding force, s a v2 s_2/s_1 = (v_2/v_1 )^2 =((80 km/h)/(40 km/h))^2 =4 s2 = 4s1 = 4 × 2 = 8m



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