1.

1). 1/√22). 2√23). √34). √2

Answer»

[(sin59°cos31° + cos59°sin31°) ÷ (cos20°cos25° - sin20°SIN 25°)]

APPLYING the FORMULA,

Sin(A + B) = SinACosB + CosASinB

Cos(A + B) = COSACOSB - SinASinB

∴ [(sin59°cos31° + cos59°sin31°) ÷ (cos20°cos25° - sin20°sin 25°)] = Sin90°/Cos45° = √2



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