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1). ½2). 3/43). 34). 3/2 |
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Answer» ⇒ given: tan θ = (4/3) ⇒ LET (3sin θ + 2COS θ)/(3sin θ - 2cos θ) = x ⇒ Divide numerator and DENOMINATOR with COS θ, we get ⇒ (5 tan θ + 3)/(5 tan θ - 3) = x ⇒ (3 × (4/3) + 2)/[3 × (4/3) - 2] = x ⇒ ((12/3) + 2)/((12/3) - 2) = x ⇒ 18/6 = x ∴ x = 3 |
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