1.

1). ½2). 3/43). 34). 3/2

Answer»

⇒ given: tan θ = (4/3)

LET (3sin θ + 2COS θ)/(3sin θ - 2cos θ) = x

⇒ Divide numerator and DENOMINATOR with COS θ, we get

⇒ (5 tan θ + 3)/(5 tan θ - 3) = x

⇒ (3 × (4/3) + 2)/[3 × (4/3) - 2] = x

⇒ ((12/3) + 2)/((12/3) - 2) = x

⇒ 18/6 = x

∴ x = 3



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