InterviewSolution
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1). sin2x > \(\frac{1}{2}\) and cos2x> \(\frac{1}{2}\)2). sin2x > \(\frac{1}{2}\) and cos2x < \(\frac{1}{2}\)3). sin2x < \(\frac{1}{2}\) and cos2x < \(\frac{1}{2}\)4). sin2x, cos2x at least one is less than 1 |
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Answer» If 0 ≤ X ≤ $(\frac{{\rm{\PI }}}{2})$ Then 0 ≤ sinx ≤ 1 0 ≤ cosx ≤ 1 sinx increases from 0° to 90° in first QUADRANT and cosx decreases. |
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