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1) 1.2JD16, n identical cubes each of mass 'm' and sideare on the horizontal surface. Then theminimum amount of work done to arrangethem one on the other is

Answer»

Work done in placing a 2ndcube on the first one, W2​ mglSimilarly W3= 2 mgl W4= 3 mgl Wn= (n -1) mglTotal work done WN= W1+ W2+ W3...+WnWN​ = [ mgl+2mgl+3mgl....(n - 1) mgl ]WN​ =mgl [ 1+2+3+......(n - 1) ]



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