1.

1). 102). 183). 154). 12.5

Answer»

Let the smaller RADIUS be M CM and larger radius be N cm.

⇒ (M + N)/2 = 12.5

⇒ (M + N) = 25

The average area of the TWO circles is 62.5 percent more than area of smaller circle.

⇒ [π M × M + π N × N]/2 = [π M × M]× (1 + 62.5/100)

⇒ M× M + N× N = 3.25M × M

⇒ N× N = 2.25M × M

⇒ N = 1.5M

⇒ M + 1.5M = 25

⇒ M = 25/2.5 = 10 and N = 1.5M = 15

∴ Radius of larger circle is 15 cm.



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