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The average of (2, 5 and 8), (13, 0 and 5) and (3, 1 and 2) is a, b and c respectively. Find the value of (7c + a × 3b)/131). 102). 83). 164). 20 |
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Answer» Average = (sum of ELEMENTS)/(number of elements) Given, The average of (2, 5 and 8), (13, 0 and 5) and (3, 1 and 2) is a, b and c respectively. ⇒ (2 + 5 + 8)/3 = a ⇒ a = 15/3 = 5 ⇒ (13 + 0 + 5)/3 = b ⇒ b = 18/3 = 6 ⇒ (3 + 1 + 2)/3 = c ⇒ c = 6/3 = 2 The value of (7c + a × 3b)/13 = {(7 × 2) + (5 × (3 × 6))}/13 = (14 + (5 × 18))/13 = (14 + 90)/13 = 104/13 = 8 ∴ The value of (7c + a × 3b)/13 is 8. |
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