1.

The average of (2, 5 and 8), (13, 0 and 5) and (3, 1 and 2) is a, b and c respectively. Find the value of (7c + a × 3b)/131). 102). 83). 164). 20

Answer»

Average = (sum of ELEMENTS)/(number of elements)

Given,

The average of (2, 5 and 8), (13, 0 and 5) and (3, 1 and 2) is a, b and c respectively.

⇒ (2 + 5 + 8)/3 = a

⇒ a = 15/3 = 5

⇒ (13 + 0 + 5)/3 = b

⇒ b = 18/3 = 6

⇒ (3 + 1 + 2)/3 = c

⇒ c = 6/3 = 2

The value of (7c + a × 3b)/13

= {(7 × 2) + (5 × (3 × 6))}/13

= (14 + (5 × 18))/13

= (14 + 90)/13

= 104/13

= 8

∴ The value of (7c + a × 3b)/13 is 8.


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