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1). 12). 7/153). 3/54). 0

Answer»

⇒ Let x = $(\frac{{\SQRT {1 - sin{\RM{\THETA }}} }}{{\sqrt {1 + sin{\rm{\theta }}} }})$

⇒ Multiplying NUMERATORAND denominator by √(1 - sinθ) we get

⇒ x = (1 - sinθ)/√(1 - sin2 θ)

⇒ x = (1 - sinθ)/√(cos2 θ)

⇒ x = SEC θ - tan θ

whentan θ = (8/15)

according to Pythagorean theorem:

Sec θ = 17/15

so,

⇒ x = (17/15) - (8/15)

∴ x = 9/15 = 3/5



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