InterviewSolution
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1). 12). 7/153). 3/54). 0 |
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Answer» ⇒ Let x = $(\frac{{\SQRT {1 - sin{\RM{\THETA }}} }}{{\sqrt {1 + sin{\rm{\theta }}} }})$ ⇒ Multiplying NUMERATORAND denominator by √(1 - sinθ) we get ⇒ x = (1 - sinθ)/√(1 - sin2 θ) ⇒ x = (1 - sinθ)/√(cos2 θ) ⇒ x = SEC θ - tan θ whentan θ = (8/15) according to Pythagorean theorem: Sec θ = 17/15 so, ⇒ x = (17/15) - (8/15) ∴ x = 9/15 = 3/5 |
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