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(1//2) mole of helium is contained in a container at STP how much heat energy is needed to double the pressure of the gas, keeping the volume constant? Heat capacity of gas is 3 J g^(-1)K^(-1). |
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Answer» Solution :`n=1/2,C_v=3j//gK . M = 4` `C_v = MC_v = 12 ` J/mole k, `M RARR` Molecular mass `P_2/P_1 =T_2/T_1=2` `DeltaT=2T_1-T_1=273k` `DeltaQ=nC_vDeltaT=1638J` |
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