InterviewSolution
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1). 2826.42). 1256.63). 2433.54). 3925.5 |
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Answer» spherical shell has an inner RADIUS of 10 cm. The outer radius is 50% more in length than inner radius. ⇒ Outer radius = 10 + (10 × (50/100)) = 15 cm After shell is cut into two equal halves, each of the halves will be a hemispherical shell. A hemispherical shell has three SURFACES: Outer curved SURFACE, inner curved surface and planar circular ring SEPARATING the two curved surfaces. Surface area of outer curved surface = 2 × π × square of outer radius Surface area of inner curved surface = 2 × π × square of inner radius Surface area of planar circular ring = π × (square of outer radius – square of inner radius) ∴ Total surface area of each of the halves = (2 × 3.14 × 15 × 15) + (2 × 3.14 × 10 × 10) + (3.14 × (15 × 15 – 10 × 10)) = 1413 + 628 + 392.5 = 2433.5 square cm |
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