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1. A bus starts from rest and attains 40 kmhin (1) km h-2 and (ii) ms?velocity after 10 seconds. Calculate the acceleration of the busAns.( 14400 km2 |
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Answer» We know,v = u + at v = final velocityu = initial velocitya = accelerationt = time t = 10 sec = 10/3600 hr 40 = 0 + a*(1/360) a = 40*360 = 14400 km/hr^2 In m/s^2a = 14400 * 1000/(3600*3600) = 14400 * (1/18*720) = 1.11 m/s^2 |
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