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1. A jet airplane travelling at the speed of 450 kmh-1ejects the burnt gases at the speed of 1200 kmh-1relative to the jet airplane. Find the speed of theburnt gases w.r.t. a stationary observer on earth.

Answer»

Velocity of jet w.r.t. groundVjg= 450 km/h …...(Upward)

Velocity of products relative to jetVPJ= 1200 km/h …(downward)

Hence, velocity of products relative to ground = -1200+450

= -750 km/h

Here – ve sing means downward .



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