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1. A particle is pwith a velocity v, so that its range on a horizontal plane is twice the greatest height attained If gis acceleration due to gravity, then its range is:A) 븐59dardB)C)业.5g?

Answer»

H = (R/4) Tanθ

Given that R = 2H

H = (H/2) TanθTanθ = 2

If Tanθ = 2 thenSinθ = 2 / √5Cosθ = 1 / √5

R = 2u² sinθ cosθ / g= (2u² × 2 / 5) / g= 4u² / (5 g)

Range of projectile is 4u² / (5g)



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