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1. A plane surface of area 200 cm2 is kept im a uniformelectric field of intensity 200 N/C. If the angle betweenthe normal to the surface and field is 60°, the electric fluxthrough the surface is |
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Answer» Since the angle from the normal of the area is = 60° so, the angle between the plane of area and the electric Field will be = 90-60 = 30° = ∅ and theFlux is given by = E×A = E.Asin∅ flux = 200* (200) × 10^-⁴ × sin30° = 2*2/2 = 2N-m²/C |
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