(1)Calculate the angular velocity andvelocity of a tip of minute hand

1.	(1)Calculate the angular velocity andvelocity of a tip of minute hand of length 10cm.
Answer» Solution:-Given –Radius of tip of minute hand = r=1 0 cm= 0.1 m. As minute hand takes one hour to complete one rotation (i.e. 360°or 2πradian); The time period of the tip of minute hand can be given as=T =1hr = 60 min = 3600 sec. The angular velocity of any particle performing circular motion can be given as time rate of change of angular displacement,W = (dθ)/ (dt) W= (2π) / TW= (2 X 3.14) / 3600W= 1.745 X 10-3rad / sec The linear velocity (v) at the tip of minute hand is V = r X wV = 0.1X 1.745 X 10-3V = 1.745 X 10-4m/s

(1)Calculate the angular velocity andvelocity of a tip of minute hand of length 10cm.

Answer»

Solution:-Given –Radius of tip of minute hand = r=1 0 cm= 0.1 m.

As minute hand takes one hour to complete one rotation (i.e. 360°or 2πradian);

The time period of the tip of minute hand can be given as=T =1hr = 60 min = 3600 sec.

The angular velocity of any particle performing circular motion can be given as time rate of change of angular displacement,W = (dθ)/ (dt)

W= (2π) / TW= (2 X 3.14) / 3600W= 1.745 X 10-3rad / sec

The linear velocity (v) at the tip of minute hand is V = r X wV = 0.1X 1.745 X 10-3V = 1.745 X 10-4m/s

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