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`(1+cosx)/(1-cosx)=tan^2x/(secx-1)^2` |
Answer» LHS=`(1+cosx)/(1-cosx)=((1+cosx)(1-cosx))/(1-cosx)^2` `=(1-cos^2x)/(1-1/secx)^2=sin^2x/((secx-1)^2/sec^2x)` `=(sin^2x*sec^2x)/(secx-1)^2` `=((sin^2x)/(cosx))/(secx-1)^2` `=tan^2x/(secx-1)^2` RHS. |
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