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1 dyne/esu = _____ N/C(a) 3*10^4(b) 10^5(c) 3*10^5(d) 9*10^4This question was posed to me in an online interview.This key question is from Electric Field Lines in section Charges and Fields of Physics – Class 12 |
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Answer» RIGHT OPTION is (a) 3*10^4 Best explanation: 1 N/C = \(\frac {1 N}{1 C} = \frac {10^5 dyne}{3*10^9 esu} = \frac {1}{3*10^4}\)dyne/esu. Therefore 1 dyne/esu=3*10^4 N/C. Both of them are the UNIT of electric field INTENSITY. But N/C is the unit of electric field intensity in the SI system while dyne/esu is the unit of field intensity in the CGS system. |
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