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1) Force experienced by charge 'q' moving withvelocity 'v' in a magnetic field 'B' is given byF= qvB. Find the dimensions of magnetic field. |
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Answer» For a charge (q) moving with a speed v under the influence of a magnetic flux density of B, the force (F) exerted is given asrnrnF = q (v x B)rnorrnB = F / qVrndimensionallyrn[B] = [MLT-2] / [AT].[LT-1]rnso, [B] = [MT -2 A -1 ] |
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