1 kg body explodes into three fragments. The ratioof their masses is 1

1.	1 kg body explodes into three fragments. The ratioof their masses is 1: 1:3. The fragments of samemass30 m/s, while the heavier part remains in the intialdirection. The speed of heavier part is:move perpendicular to each other with speeds10豆m(B) 10/2 m/s(C) 20 v2 m/s(D) 30 -/2 m/s
Answer» Masses of fragments: 1/5 * 1kg, 1/5* 1kg, 3/5 * 1kg ie., 0.2 kg, 0.2 kg, 0.6 kg Linear momentum of theirs: 0.2 * 30m/s = 6 kg-m/s, 6 kg-m/s, 0.6 * v kg-m/s The vector sum of the first two : 6√2 kg-m/s as they two linear momenta are perpendicular. This will be in North East direction, if the two pieces fly off in North and East directions respectively. So linear momentum of the large piece is in the direction of South West direction as Linear momentum of all three pieces is 0 (as before explosion). Velocity of the third piece = 6√2 kg-m/s / 0.6 kg = 10√2 m/s

1 kg body explodes into three fragments. The ratioof their masses is 1: 1:3. The fragments of samemass30 m/s, while the heavier part remains in the intialdirection. The speed of heavier part is:move perpendicular to each other with speeds10豆m(B) 10/2 m/s(C) 20 v2 m/s(D) 30 -/2 m/s

Answer»

Masses of fragments: 1/5 * 1kg, 1/5* 1kg, 3/5 * 1kg ie., 0.2 kg, 0.2 kg, 0.6 kg

Linear momentum of theirs: 0.2 * 30m/s = 6 kg-m/s, 6 kg-m/s, 0.6 * v kg-m/s

The vector sum of the first two : 6√2 kg-m/s as they two linear momenta are perpendicular. This will be in North East direction, if the two pieces fly off in North and East directions respectively.

So linear momentum of the large piece is in the direction of South West direction as Linear momentum of all three pieces is 0 (as before explosion).

Velocity of the third piece = 6√2 kg-m/s / 0.6 kg = 10√2 m/s

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