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1. Program to find sum of series 1 + 1/2 + 1/3 + 1/4 +...+ 1/n.

Answer»

tion:#include USING namespace std; Function to return sum of 1/1 + 1/2 + 1/3 + ..+ 1/n { double sum(INT n) { double i, s = 0.0; for (i = 1; i <= n; i++) s = s + 1/i; return s; } }; int MAIN() { gfg g; int n = 5; cout << "Sum is " << g.sum(n); return 0; }


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