1.

1). sin x2). cosx3). -1 + sin x4). 1 - cosx

Answer»

$(\because 1 - {\sin ^2}x = \LEFT( {1 - \sin x} \right)\left( {1 + \sin x} \right))$

$(\FRAC{{\left( { - 1} \right)\left( {1{\RM{\;}} + {\rm{\;sinx}}} \right)\left( {1 - \sin {\rm{x}}} \right)}}{{\sin {\rm{x\;}} + {\rm{\;}}1}} = \sin {\rm{x}} - 1)$



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