1.

1.Three copper wires have their lengths in the ratio5:3:1 and their masses are in the ratio 1:35. Their electrical resistance will be in the ratiopls with explanation​

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Resistance of a WIRE is given as

A

ρL

This is the same as

A×L

ρL

2

=

V

ρL

2

So, resistance is proportional to

M

L

2

The RATIO of resistances is,

1

25

:

3

9

:

5

1

=125:15:1



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