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1. Three point charges are placed at the followingpoints on the X-axis 2uC at x 0 -3 uC atx 40cm and-5 μC at x 120 cm. Calculate theforce on the - 3uC charge.

Answer»

Fe= (-9.0 * 10^9) * (2.0 * 10^-6)(3.0 * 10^-6) / 0.40^2= -54 * 10^-3 / 1.6 * 10^-1= -0.3375 N

Fe= (-9.0 * 10^9) * (-5.0 * 10^-6)(3.0 * 10^-6) / 0.80^2= 135 * 10^-3 / 6.4 * 10^-1= -0.2109 N

a = -0.55N



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