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1) Two blocks of mass 1kg and 2kg are connected by an in extensiblestring which passes over a frictionless pulley as shown in figure.calculate the acceleration of these blocks. |
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Answer» Let the acceleration a ACT towards right so that the block of MASS 2 kg goes down and that of 1 kg mass goes up ALONG the plane DUE to this. From the FBD of the block of mass 1 kg, T - 5√3 = a → (1) And from the FBD of the block of mass 2 kg, 10 - T = 2a → (2) Now, adding (1) and (2), 10 - 5√3 = 3a a = [5(2 - √3) / 3] m s^(-2)a = 0.447 m s^(-2) |
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