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1. What should be the position of charge q = 5uC for it to be in equilibrium onthe line joining two charges q, =-4 uC and q2 = 16 uC separated by 9 cm.Will the position change for any other value of charge q ? |
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Answer» Answer: NET force is zero and F1= K. -4.5/x. F2= k. 16.5/9+x. F1=f2 after solving we will get x=9cm by -4uc |
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