InterviewSolution
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InterviewSolution
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`(1+x^(2))dy+2xy dy=cotxdx(xne0)` |
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Answer» `(1+x^(2))dy+2xy dx=cotxdx` `implies(dy)/(dx)+(2x)/(1+x^(2))y=(cotx)/(1+x^(2))` यहाँ, `P=(2x)/(1+x^(2)),Q=(cotx)/(1+x^(2))` `therefore I.F. =e^(int(2x)/(1+x^(2))dx)=e^(log(1+x^(2)))=(1+x^(2))` और व्यापक हल : `y(1+x^(2))=int(cotx)/(1+x^(2))(1+x^(2))dx+c` `=intcotxdx+c` `implies y(1+x^(2))=logsinx+c` |
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