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`(1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2)),y=0` यदि x = 1 |
Answer» `(1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2))` `implies (dy)/(dx)+(2x)/(1+x^(2))y=(1)/((1+x^(2))^(2))` यहाँ, `P=(2x)/(1+x^(2))` तथा `Q=(1)/((1+x^(2))^(2))` `I.F.=e^(intPdx)=e^(int(2x)/(1+x^(2))dx)` `therefore =e^(log(1+x^(2)))=(1+x^(2))` |
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