InterviewSolution
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InterviewSolution
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10. A large number of identical point masses m areplaced along x-axis, at x 0, 1, 2, 4,magnitude of gravitational force on mass at origi(x-0), will be.. Thex=0 x = 1 x=2x=4 and so on4(2) G23(1) Gm22(3) Gm2(4)Grif4 |
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Answer» The magnitude of gravitational force on mass at origin is given by, F=G×m×m/1^1+G×m×m/2^2+G×m×m/4^2+G×m×m/8^2+...... [Using,F=GMM'/r^2 Given,M=M'=m] So,F=Gm×m[1+1/4+1/16+...]=Gm^2[1/4/1−1/4⎤⎦=Gm^2×1/3=Gm^2/3 but its given 4/3 Gm^2 |
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