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10 g of argon is compressd isothermally and reversibly at a temperature of`27^(@)C` from 10L to 5L . Calculate q,w,`DeltaE` and `DeltaH ` for this process. `R =2.0 cal K^(-1) mol^(-1) , log= 2 = 0.30`. Atomic wt. of Ar`=40`

Answer» `q= 2.303 nRT log. (V_(2))/(V_(1)) = 2.303 xx (10)/( 40) xx 300 xx log. (5)/(10)= -103.635 cal`
For isothermal expansion,`DeltaE= 0` `w= DeltaE-q= 0-( - 103.635)= +103.635 cal`
Also, when temperature is constant, `P_(1)V_(1) = P_(2)V_(2)` or `PV =` constant `DeltaH = DeltaE +Delta(PV) = 0+0=0`


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