InterviewSolution
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InterviewSolution
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10. What is the time required for a block to slide down from the top to the bottom of aninclined plane 6.4 m long if the inclination of the plane with the horizontal is 30° andthe coefficient of friction 0.2 ?(2) 1.5 s(3) 3 s(4) 2.5 s |
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Answer» acceleration of block due to gravity on the plane is given by; a = g SinΘ - f / m a = g SinΘ - µR CosΘ / m a = g SinΘ - µmg CosΘ / m a = 9.8 x Sin 30 - µg CosΘ a = 4.9 - (0.2)(9.8) Cos (30) a = 4.9 - 1.697 a = 3.20 m/s^2 t = ? If S = 6.4m S = Ut + 1/2at^2 .................. U = initial velocity = 0 at the top of inclined plane 6.4 = 0 + 1/2(3.2)t^2 6.4 = 1.6t^2 => t^2 = 6.4 / 1.6 => t^2 = 4 => √ t^2 = t = 2 seconds thank you very much |
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