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100 `cm^(3)` of 0.1 N HCl solution is mixed with 100 `cm^(3)` of 0.2 N NaOH solution. The resulting solution isA. 0.1 N and the solution is basicB. 0.05 N and the solution is basicC. 0.1 N and the solution is acidicD. 0.05 N ad the solution is acidic |
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Answer» Correct Answer - B Acid=0.1`xx100=10` base`=0.2xx100=20` `therefore` Solution will be basic. 0.1 N of HCl is neutralised by 0.1 N of NaOH and the remaining 0.1 N of NaOH is in 200 `cm^(3)` of solution. `therefore` Resulting normality`=0.5`N, basic. |
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