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11. A golfer hits a 42 g ball, which comes down on a tree root and bounces straight up with an initial speed of 15.6 m/s. Determine the height the ball will rise after the bounce. Show all your work.

Answer»

Explanation:

Given:-

  • Mass of BALL ,m = 42g

  • Initial velocity ,u = 15.6m/s

  • Final velocity ,V = 0m/s

  • Acceleration due to gravity ,g = 9.8m/s

To Find:-

  • Height ,h

Solution:-

We have to calculate the height ATTAINED by the ball after bounce. Using 3rd Equation of Motion

• v² = u² +2gh

v is the final velocity

g is the acceleration

u is the initial velocity

h is the height attained

Substitute the value we get

→ 0² = 15.6² + 2×(-9.8) × h

→ 0 = 243.36 + (-19.6) ×h

→ -243.36 = -19.6×h

→ h = -243.36/-19.6

→ h = 243.36/19.6

→ h = 12. 41 m

Therefore, the height attained by the ball is 12.41 Metres.


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